如何将HttpPostedFileBase对象序列化为json

Question

我有一个在控制器中名为'Upload'的方法，它带有一个参数HttpPostedFileBase对象。我从视图中提交了文件并成功地将其保存到文件夹中。但是，当我尝试返回以下内容的JSON字符串对象时，它会抛出异常，消息：

"Error getting value from 'ReadTimeout' on 'System.Web.HttpInputStream'."

如果我删除'files = files'这一行，则可以正确返回。但我需要这些数据。

public string Upload(HttpPostedFileBase files)
{
    try
    {          
        if (files != null && files.ContentLength > 0)
        {
            var path = Path.Combine(Server.MapPath("~/Uploads"), files.FileName);
            files.SaveAs(path);
            return JsonConvert.SerializeObject(
                new
            {
                files=files,
                Passed = true,
                Mesaj = "item added"
            });
        }
    }
}

- TyForHelpDude

Answer 1

您可以像这样创建自定义的JsonConverter：

public class HttpPostedFileConverter : JsonConverter
{
        public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
        {
            var stream = (Stream)value;
            using (var sr = new BinaryReader(stream))
            {
                var buffer = sr.ReadBytes((int)stream.Length);
                writer.WriteValue(Convert.ToBase64String(buffer));
            }
        }

        public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
        {
            throw new NotImplementedException();
        }

        public override bool CanRead
        {
            get { return false; }
        }

        public override bool CanConvert(Type objectType)
        {
            return objectType.IsSubclassOf(typeof(Stream));
        }
    }

并将其传递给JsonConvert.SerializeObject方法

return JsonConvert.SerializeObject(
                    new
                    {
                        files=files,
                        Passed = true,
                        Mesaj = "item added"
                    }, 
                    new HttpPostedFileConverter());

- Arthur Smirnov