table: room
columns: id, maxGuests
table: roombooking
columns: id, startDate, endDate
table: roombooking_room:
columns: id, room_id, roombooking_id
我需要选择可以容纳所需客人的房间,或者选择两个(或更多)房间以适应客人(根据maxGuests定义,显然首先使用最低/最接近的maxGuests)
我可以循环我的日期范围并使用以下sql:
SELECT `id`
FROM `room`
WHERE `id` NOT IN
(
SELECT `roombooking_room`.`room_id`
FROM `roombooking_room`, `roombooking`
WHERE `roombooking`.`confirmed` =1
AND DATE(%s) BETWEEN `roombooking`.`startDate` AND `roombooking`.`endDate`
)
AND `room`.`maxGuests`>=%d
其中%$1是循环的日期,%2d是要预订的客人数量。但如果客人超过任何一个房间可以容纳的人数,这只会返回false,必须有一种更快的方法来做到这一点,而不是用php循环并运行查询?
这类似于我正在考虑的sql的一部分:在日期范围内获取日期,但使用Mysql
基于ircmaxwell的答案,解决方案如下:
$query = sprintf(
"SELECT `id`, `maxGuests`
FROM `room`
WHERE `id` NOT IN
(
SELECT `roombooking_room`.`room_id`
FROM `roombooking_room`
JOIN `roombooking` ON `roombooking_room`.`roombooking_id` = `roombooking`.`id`
WHERE `roombooking`.`confirmed` =1
AND (`roomBooking`.`startDate` > DATE(%s) OR `roomBooking`.`endDate` < DATE(%s))
)
AND `maxGuests` <= %d ORDER BY `maxGuests` DESC",
$endDate->toString('yyyy-MM-dd'), $startDate->toString('yyyy-MM-dd'), $noGuests);
$result = $db->query($query);
$result = $result->fetchAll();
$rooms = array();
$guests = 0;
foreach($result as $res) {
if($guests >= $noGuests) break;
$guests += (int)$res['maxGuests'];
$rooms[] = $res['id'];
}