我有两个数组,array1包含了从上午8点到下午2点每分钟的日期时间数据,而array2则包含了同一天上午8点到下午1点每小时的日期时间数据。
我想输出两个数组中具有相同datetime.hour的索引号,并且它应该匹配array2的最后可用索引号,以便对于所有晚于array2的datetime数据,都可以匹配上。
例如,如果我有两个如下的datetime数组:
DateTime[] dateTimes1 = new DateTime[]
{
new DateTime(2010, 10, 1, 8, 15, 0),
new DateTime(2010, 10, 1, 8, 30, 1),
new DateTime(2010, 10, 1, 8, 45, 2),
new DateTime(2010, 10, 1, 9, 15, 3),
new DateTime(2010, 10, 1, 9, 30, 4),
new DateTime(2010, 10, 1, 9, 45, 5),
new DateTime(2010, 10, 1, 10, 15, 6),
new DateTime(2010, 10, 1, 10, 30, 7),
new DateTime(2010, 10, 1, 10, 45, 8),
new DateTime(2010, 10, 1, 11, 15, 9),
new DateTime(2010, 10, 1, 11, 30, 10),
new DateTime(2010, 10, 1, 11, 45, 11),
new DateTime(2010, 10, 1, 12, 15, 12),
new DateTime(2010, 10, 1, 12, 30, 13),
new DateTime(2010, 10, 1, 12, 45, 14),
new DateTime(2010, 10, 1, 13, 15, 15),
new DateTime(2010, 10, 1, 13, 30, 16),
new DateTime(2010, 10, 1, 13, 45, 17),
new DateTime(2010, 10, 1, 14, 15, 18),
new DateTime(2010, 10, 1, 14, 30, 19),
new DateTime(2010, 10, 1, 14, 45, 20),
};
DateTime[] dateTimes2 = new DateTime[]
{
new DateTime(2010, 10, 1, 8, 0, 0),
new DateTime(2010, 10, 1, 9, 0, 1),
new DateTime(2010, 10, 1, 10, 0, 2),
new DateTime(2010, 10, 1, 11, 0, 3),
new DateTime(2010, 10, 1, 12, 0, 4),
new DateTime(2010, 10, 1, 13, 0, 5),
};
应该给我输出:
0, 0
1, 0
2, 0
3, 1
4, 1
5, 1
6, 2
7, 2
8, 2
9, 3
10, 3
11, 3
12, 4
13, 4
14, 4
15, 5
16, 5
17, 5
18, 5
19, 5
20, 5
这是我尝试的:
int i = 0;
int j = 0;
while (i < dateTimes1.Length && j < dateTimes2.Length)
{
if (dateTimes1[i].Date == dateTimes2[j].Date && dateTimes1[i].Hour == dateTimes2[j].Hour)
{
list.Add(i);
list2.Add(j);
i++;
}
else if (dateTimes1[i] < dateTimes2[j])
{
i++;
}
else if (dateTimes1[i] > dateTimes2[j])
{
j++;
}
}
for (int k = 0; k < list.Count; k++)
{
Console.WriteLine(list[k] + " , " + list2[k];
}
但是在下午1点后,它不会输出索引号。