根据Compojure路由文档,我可以轻松地获取单个参数,如下所示:
(POST "/my-app" [param1 param2]
(str "<h1>Hello " param1 " and " param2 "</h1>"))
如何获取所有参数,而不仅仅是单个参数?
(POST "/my-app" [param1 param2]
(str "<h1>Hello " param1 " and " param2 "</h1>"))
如何获取所有参数,而不仅仅是单个参数?
Compojure处理程序接收整个请求映射作为它们的参数,因此处理程序也可以访问所有参数。例如,要查看整个请求:
(POST "/" request
(str request))
(POST "/" request
(str (:form-params request)))
问题中使用的语法是特定于compojure的解构语法,它允许从请求中提取单个参数。这类似于clojure的常规解构语法,并且与常规解构一样,compojure的解构也允许混合解构并仍然获取整个请求:
(POST "/" [param1 param2 :as request]
(str (:form-params request)))
(POST "/" [param1 param2 & more-params]
(str more-params))
我猜测把& params
放入向量中即可解决问题:
(POST "/my-app" [& params]
(str "<h1>Hello " params "</h1>"))
类似这样返回所有参数:
(POST "/test" {params :params}
(str "POST params=" params))
(println (params :Nom))