我在使用OpenXML的MemoryStream时遇到了问题。如果我在单个方法中完成所有步骤,则可以成功打开Word文件、更改它并通过HttpResponse下载它。
但是,如果我尝试在两个不同的类(或方法)中返回MemoryStream,那么我会得到一个损坏的word文件。我认为这可能是刷新或缓冲区问题,但我找不到解决方案。
以下是可行的代码:
public void FillTemplateOpenXmlWord(HttpResponse response)
{
string filePath = @"c:\template.docx";
byte[] filebytes = File.ReadAllBytes(filePath);
using (MemoryStream stream = new MemoryStream(filebytes))
{
using (WordprocessingDocument myDoc = WordprocessingDocument.Open(stream, true))
{
// do some changes
...
myDoc.MainDocumentPart.Document.Save();
}
string docx = "docx";
response.Clear();
response.ClearHeaders();
response.ClearContent();
response.AddHeader("content-disposition", "attachment; filename=\"" + docx + ".docx\"");
response.ContentType = "application/vnd.openxmlformats-officedocument.wordprocessingml.document";
response.ContentEncoding = Encoding.GetEncoding("ISO-8859-1");
stream.Position = 0;
stream.CopyTo(response.OutputStream);
response.End();
}
}
以下是不工作的代码:
public void OpenFile(HttpResponse response)
{
MemoryStream stream = this.FillTemplateOpenXmlWord();
string docx = "docx";
response.Clear();
response.ClearHeaders();
response.ClearContent();
response.AddHeader("content-disposition", "attachment; filename=\"" + docx + ".docx\"");
response.ContentType = "application/vnd.openxmlformats-officedocument.wordprocessingml.document";
response.ContentEncoding = Encoding.GetEncoding("ISO-8859-1");
stream.Position = 0;
stream.CopyTo(response.OutputStream);
response.End();
}
public MemoryStream FillTemplateOpenXmlWord()
{
string filePath = @"c:\template.docx";
byte[] filebytes = File.ReadAllBytes(filePath);
using (MemoryStream stream = new MemoryStream(filebytes))
{
using (WordprocessingDocument myDoc = WordprocessingDocument.Open(stream, true))
{
// do some changes
...
myDoc.MainDocumentPart.Document.Save();
}
return stream;
}
}
有什么想法吗?
谢谢。