安卓KSOAP2向PHP SOAP服务器发送请求

4
我正在尝试在我的安卓应用程序中创建一个SOAP客户端。我已经使用php SOAP客户端测试了服务器,它是可行的。但是在我的安卓应用程序中,我仍然遇到异常。有人可以帮我找出问题并解决吗?谢谢。
PHP
<?php
class service
{      
public function service()
{   }

public function login($nickname, $password)
{   

    $sql = "select nick from user 
    where 
    nick =\"$nick\"
    and
    pass = \"$password\"";

    if (($result = $this->db->query($sql)) && ($result->num_rows == 1))
        return true;
    else
        return false;
}  
}

$server = new SoapServer(null, array(
'uri' => "urn://www.domain.cz",
'soap_version' => SOAP_1_2)
);              
$server->setClass("service");     
$server->handle(); 
?>

安卓操作系统

private static String SOAP_ACTION = "http://www.domain.cz/server/server.php";
    private static String NAMESPACE = "urn://www.domain.cz";
    //need fix namespace to work, final solution
    // private static String NAMESPACE = "http://www.domain.cz/server/";
    private static String METHOD_NAME = "login";
    private static String URL = "http://www.domain.cz";

public void Connect()
{
    //Initialize soap request + add parameters
    SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);

    //Use this to add parameters
    request.addProperty("nick","peter");
    request.addProperty("password","somepassword");

    //Declare the version of the SOAP request
    SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER12);
    envelope.setOutputSoapObject(request);

    //Needed to make the internet call
    HttpTransportSE androidHttpTransport = new HttpTransportSE(URL);
    try {
            //this is the actual part that will call the webservice
            androidHttpTransport.call(SOAP_ACTION, envelope);//HERE is xmlpullparserexception after a while
    } catch (Exception e) {
            e.printStackTrace();
    }

    // Get the SoapResult from the envelope body.
    SoapObject result = (SoapObject)envelope.bodyIn;

    if(result != null){
            TextView t = (TextView)this.findViewById(R.id.resultbox);

            //Get the first property and change the label text
            t.setText("SOAP response:\n\n" + result.getProperty(0).toString());
    }

}

1
你得到的确切异常是什么? - Paul-Jan
2个回答

2

您的URL应该是SOAP端点,即http://www.domain.cz/server/server.php

您的SOAP_ACTION应包含方法名称,即http://www.domain.cz/server/server.php/login


0

我猜你正在使用KSOAP。我认为你需要将URL指向Web服务路径。我在你的URL上看不到WSDL。


是的,我正在使用KSOAP。 我认为我可以在没有WSDFL文件的情况下使用它。如果KSOAP不能在没有WSDL的情况下工作,是否有其他方法? - zdarsky.peter

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