我正在开发我的第一个Spring Security应用程序。我的applicationContext-security.xml文件如下所示：
<?xml version="1.0" encoding="UTF-8"?>
<!--
- Namespace-based OpenID configuration
-->
<b:beans xmlns="http://www.springframework.org/schema/security"
xmlns:b="http://www.springframework.org/schema/beans"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd
http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd">
<http>
<intercept-url pattern="/**" access="ROLE_USER"/>
<intercept-url pattern="/index.xhtml*" filters="none"/>
<logout/>
<openid-login login-page="/index.xhtml" authentication-failure-url="/index.xhtml?login_error=true">
<attribute-exchange>
<openid-attribute name="email" type="http://schema.openid.net/contact/email" required="true" count="2"/>
<openid-attribute name="name" type="http://schema.openid.net/namePerson/friendly" />
</attribute-exchange>
</openid-login>
<remember-me token-repository-ref="tokenRepo"/>
</http>
<b:bean id="tokenRepo"
class="org.springframework.security.web.authentication.rememberme.InMemoryTokenRepositoryImpl" />
<authentication-manager alias="authenticationManager"/>
<user-service id="userService">
<user name="http://user.myopenid.com/" authorities="ROLE_SUPERVISOR,ROLE_USER" />
</user-service>
</b:beans>
Web.xml文件长这样：
<?xml version="1.0" encoding="UTF-8"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"
xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"
xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd" version="2.4">
<display-name>Spring Security OpenID Demo Application</display-name>
<context-param>
<param-name>contextConfigLocation</param-name>
<param-value>
/WEB-INF/applicationContext-security.xml
</param-value>
</context-param>
<context-param>
<param-name>log4jConfigLocation</param-name>
<param-value>/WEB-INF/classes/log4j.properties</param-value>
</context-param>
<context-param>
<param-name>webAppRootKey</param-name>
<param-value>openid.root</param-value>
</context-param>
<filter>
<filter-name>springSecurityFilterChain</filter-name>
<filter-class>org.springframework.web.filter.DelegatingFilterProxy</filter-class>
</filter>
<filter-mapping>
<filter-name>springSecurityFilterChain</filter-name>
<url-pattern>/*</url-pattern>
</filter-mapping>
<listener>
<listener-class>org.springframework.web.context.ContextLoaderListener</listener-class>
</listener>
<listener>
<listener-class>org.springframework.web.util.Log4jConfigListener</listener-class>
</listener>
<welcome-file-list>
<welcome-file>faces/index.xhtml</welcome-file>
</welcome-file-list>
</web-app>
应用程序的清理和构建成功，但当我尝试部署应用程序时，Jetty 7会给我以下错误：
SEVERE：上下文初始化失败
org.springframework.beans.factory.parsing.BeanDefinitionParsingException：配置问题：无法找到XML模式名称空间的Spring NamespaceHandler[http://www.springframework.org/schema/security]
冒犯资源：ServletContext资源[/WEB-INF/applicationContext-security.xml]
在org.springframework.beans.factory.parsing.FailFastProblemReporter.error（FailFastProblemReporter.java:68）
在org.springframework.beans.factory.parsing.ReaderContext.error（ReaderContext.java:85）
在org.springframework.beans.factory.parsing.ReaderContext.error（ReaderContext.java:80）
尝试了所有方法但无法解决此错误。任何帮助将不胜感激。
编辑 我尝试添加了Spring-Security的3.0.2版本，并得到以下结果：
上下文初始化失败
org.springframework.beans.factory.xml.XmlBeanDefinitionStoreException：来自ServletContext资源[/WEB-INF/applicationContext-security.xml]中XML文档中的第13行无效；
嵌套异常是org.xml.sax.SAXParseException；行号：13；列号：11；cvc-complex-type.2.4.c：匹配通配符是严格的，但没有找到元素'http'的声明。 在org.springframework.beans.factory.xml.XmlBeanDefinitionReader.doLoadBeanDefinitions（XmlBeanDefinitionReader.java:396）
在org.springframework.beans.factory.xml.XmlBeanDefinitionReader.loadBeanDefinitions（XmlBeanDefinitionReader.java:334）