登录对话框 PyQt

Question

登录对话框 PyQt

16

我的应用程序快要完成了，顾客却要求我在应用程序启动时实现一种登录表单。

到目前为止，我已经设计好了UI并进行了实际执行的调整。用户名和密码现在还不相关。

class Login(QtGui.QDialog):
    def __init__(self,parent=None):
        QtGui.QWidget.__init__(self,parent)
        self.ui=Ui_dlgLogovanje()
        self.ui.setupUi(self)

        QtCore.QObject.connect(self.ui.buttonLogin, QtCore.SIGNAL("clicked()"), self.doLogin)

    def doLogin(self):
        name = str(self.ui.lineKorisnik.text())
        passwd = str(self.ui.lineSifra.text())
        if name == "john" and passwd =="doe":
            self.runIt()
        else:
            QtGui.QMessageBox.warning(self, 'Greška',
        "Bad user or password", QtGui.QMessageBox.Ok)           

    def runIt(self):
        myprogram = Window()        
        myprogram.showMaximized() #myprogram is

class Window(QtGui.QMainWindow):
    def __init__(self,parent=None):
        QtGui.QWidget.__init__(self,parent)
        self.ui=Ui_MainWindow()
        self.ui.setupUi(self)


if __name__=="__main__":
    program = QtGui.QApplication(sys.argv)
    myprogram = Window()
    if Login().exec_() == QtGui.QDialog.Accepted:       
        sys.exit(program.exec_())

登录表单已显示。如果输入正确的用户名和密码，则会显示主窗口并正常工作。但是，登录表单仍然处于活动状态，如果我关闭它，主窗口也会关闭。

- ivica

4

顺便说一下，QtCore.QObject.connect(self.ui2.buttonLogin, QtCore.SIGNAL("clicked()"), self.doLogin) 可以替换为 self.ui2.buttonLogin.clicked.connect(self.doLogin)。 - warvariuc

1个回答

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- ekhumoro · Accepted Answer

QDialog有自己的事件循环，因此它可以与主应用程序分开运行。

您只需要检查对话框的返回代码，以决定是否应该运行主应用程序。

示例代码（PyQt5）：

from PyQt5 import QtWidgets
# from mainwindow import Ui_MainWindow

class Login(QtWidgets.QDialog):
    def __init__(self, parent=None):
        super(Login, self).__init__(parent)
        self.textName = QtWidgets.QLineEdit(self)
        self.textPass = QtWidgets.QLineEdit(self)
        self.buttonLogin = QtWidgets.QPushButton('Login', self)
        self.buttonLogin.clicked.connect(self.handleLogin)
        layout = QtWidgets.QVBoxLayout(self)
        layout.addWidget(self.textName)
        layout.addWidget(self.textPass)
        layout.addWidget(self.buttonLogin)

    def handleLogin(self):
        if (self.textName.text() == 'foo' and
            self.textPass.text() == 'bar'):
            self.accept()
        else:
            QtWidgets.QMessageBox.warning(
                self, 'Error', 'Bad user or password')

class Window(QtWidgets.QMainWindow):
    def __init__(self, parent=None):
        super(Window, self).__init__(parent)
        # self.ui = Ui_MainWindow()
        # self.ui.setupUi(self)

if __name__ == '__main__':

    import sys
    app = QtWidgets.QApplication(sys.argv)
    login = Login()

    if login.exec_() == QtWidgets.QDialog.Accepted:
        window = Window()
        window.show()
        sys.exit(app.exec_())

示例代码（PyQt4）：

from PyQt4 import QtGui
# from mainwindow import Ui_MainWindow

class Login(QtGui.QDialog):
    def __init__(self, parent=None):
        super(Login, self).__init__(parent)
        self.textName = QtGui.QLineEdit(self)
        self.textPass = QtGui.QLineEdit(self)
        self.buttonLogin = QtGui.QPushButton('Login', self)
        self.buttonLogin.clicked.connect(self.handleLogin)
        layout = QtGui.QVBoxLayout(self)
        layout.addWidget(self.textName)
        layout.addWidget(self.textPass)
        layout.addWidget(self.buttonLogin)

    def handleLogin(self):
        if (self.textName.text() == 'foo' and
            self.textPass.text() == 'bar'):
            self.accept()
        else:
            QtGui.QMessageBox.warning(
                self, 'Error', 'Bad user or password')

class Window(QtGui.QMainWindow):
    def __init__(self, parent=None):
        super(Window, self).__init__(parent)
        # self.ui = Ui_MainWindow()
        # self.ui.setupUi(self)    

if __name__ == '__main__':

    import sys
    app = QtGui.QApplication(sys.argv)
    login = Login()

    if login.exec_() == QtGui.QDialog.Accepted:
        window = Window()
        window.show()
        sys.exit(app.exec_())