我正在尝试使用Sidekiq运行以下工作。
当不排队(perform_now)时,该工作可以正常执行,但在使用Sidekiq调用(perform_later)时失败。
AddEmployeesToRoomJob.perform_now room ## works fine
AddEmployeesToRoomJob.perform_later room ## breaks in Sidekiq
错误:
AddEmployeesToRoomJob JID-da24b13f405b1ece1212bbd5 INFO: fail: 0.003 sec
2016-08-20T14:57:16.645Z 19456 TID-owmym5fbk WARN: {"class":"ActiveJob::QueueAdapters::SidekiqAdapter::JobWrapper","wrapped" :"AddEmployeesToRoomJob","queue":"default","args": [{"job_class":"AddEmployeesToRoomJob","job_id":"0ba5bd30-e281-49a7-a93f- 6e50445183ac","queue_name":"default","priority":null,"arguments": [{"_aj_globalid":"gid://dragonfly/Room/1"}],"locale":"en"}],"retry":true, "jid":"da24b13f405b1ece1212bbd5","created_at":1471704675.739077,"enqueued _at":1471705036.6406531,"error_message":"Error while trying to deserialize arguments: Couldn't find Room with 'id'=1","error_class":"ActiveJob::DeserializationError","failed_at":14717 04675.946183,"retry_count":4,"retried_at":1471705036.644416}
2016-08-20T14:57:16.645Z 19456 TID-owmym5fbk WARN: ActiveJob::DeserializationError: Error while trying to deserialize arguments: Couldn't find Room with 'id'=1
2016-08-20T14:57:16.645Z 19456 TID-owmym5fbk WARN: /Users/tamlyn/.rvm/gems/ruby-2.2.3/gems/activerecord- 5.0.0.1/lib/active_record/relation/finder_methods.rb:357:in `raise_record_not_found_exception!'
我的工作 AddEmployeesToRoomJob类 < ApplicationJob 队列名称:默认队列
def perform(room)
employees = Employee.all
if employees.length > 0
employees.each do |employee|
UserRoom.create(user: employee, room: room)
end
end
end
end
我的想法 我不明白为什么在执行方法时,它找不到我传递的房间。好像在将任务压入队列/转换为JSON时,该变量以某种方式丢失了?
Sidekiq文档说
“不幸的是,这意味着如果[房间]记录在作业入队之后删除但在调用执行方法之前,则异常处理会有所不同。”
他们提出了一种解决方法,但我不知道那如何帮助我:
rescue_from ActiveJob::DeserializationError do |exception|
# handle a deleted user record
end
非常感谢您提供的任何帮助!