我创建了一个Flutter应用程序,需要将其连接到本地网络套接字服务。如下所示,我可以使用telnet连接,发送数据并从服务器接收数据。我使用Flutter web_socket插件和示例。我可以连接到服务器并发送数据,但无法捕获(或获取数据,它不显示任何内容)。在Flutter谷歌组中,有人建议我使用流而不是StreamBuilder。
To send data I use; Q101:_:49785:_:ABCDE
And receive data I get; 1:_:2:_:119351:_:NİYAZİ TOROS
当我使用这个示例(https://flutter.io/cookbook/networking/web-sockets/)时,我的socket服务出现错误:
Q: 28.06.2018 08:53:57->GET / HTTP/1.1
A: 28.06.2018 08:53:57 ->:1:_:1:_:FAIL1
例子:
Last login: Tue Jun 26 15:01:44 on ttys000
Niyazis-MBP:~ niyazitoros$ telnet
telnet> telnet 192.168.1.22 1024
Trying 192.168.1.22...
Connected to 192.168.1.22.
Escape character is '^]'.
Q101:_:49785:_:*************
1:_:2:_:119351:_:NİYAZİ TOROS
根据@Richard Heap的建议:
import 'dart:async';
import 'dart:convert';
import 'dart:io';
void connect(InternetAddress clientAddress, int port) {
Future.wait([RawDatagramSocket.bind(InternetAddress.anyIPv4, 0)]).then(
(values) {
RawDatagramSocket _socket = values[0];
_socket.listen((RawSocketEvent e) {
print(e);
switch (e) {
case RawSocketEvent.read:
Datagram dg = _socket.receive();
if (dg != null) {
dg.data.forEach((x) => print(x));
}
_socket.writeEventsEnabled = true;
break;
case RawSocketEvent.write:
_socket.send(
new Utf8Codec().encode('Hello from client'), clientAddress, port);
break;
case RawSocketEvent.closed:
print('Client disconnected.');
}
});
});
}
main(List<String> arguments) {
print("Connecting to server..");
var address = new InternetAddress('192.168.1.22');
int port = 1024;
connect(address, port);
}
我得到了这个:
/Users/niyazitoros/flutter/bin/cache/dart-sdk/bin/dart --enable-asserts --enable-vm-service:59683 /Users/niyazitoros/IdeaProjects/github/untitled/bin/main.dart
Observatory listening on http://127.0.0.1:59683/
Connecting to the server.
RawSocketEvent.write
}).catchError((Object e) {
来避免“Invalid argument (onError): Error handler must accept one Object...”的错误。 - Bob Hoeppner