我有两个HTML输入框，需要在JavaScript onBlur事件中计算时间差（因为我需要实时计算），并将结果插入到新的输入框中。
格式示例：10:00和12:30需要给出02:30。
谢谢！
格式示例：10:00和12:30需要给出02:30。
谢谢！
12个回答
49
这里是一个可能的解决方案：
function diff(start, end) {
start = start.split(":");
end = end.split(":");
var startDate = new Date(0, 0, 0, start[0], start[1], 0);
var endDate = new Date(0, 0, 0, end[0], end[1], 0);
var diff = endDate.getTime() - startDate.getTime();
var hours = Math.floor(diff / 1000 / 60 / 60);
diff -= hours * 1000 * 60 * 60;
var minutes = Math.floor(diff / 1000 / 60);
// If using time pickers with 24 hours format, add the below line get exact hours
if (hours < 0)
hours = hours + 24;
return (hours <= 9 ? "0" : "") + hours + ":" + (minutes <= 9 ? "0" : "") + minutes;
}
- VisioN
2
我想在这里显示秒数。我该怎么做？ - Chinmay235
出色的解决方案，完美地满足了我的需求。甚至可以计算跨越午夜的小时数。 - Tim
6
简而言之
一次性运行
const t1 = new Date(1579876543210) // your initial time
const t2 = new Date(1579987654321) // your later time
const diff = t2-t1
const SEC = 1000, MIN = 60 * SEC, HRS = 60 * MIN
const humanDiff = `${Math.floor(diff/HRS)}:${Math.floor((diff%HRS)/MIN).toLocaleString('en-US', {minimumIntegerDigits: 2})}:${Math.floor((diff%MIN)/SEC).toLocaleString('en-US', {minimumIntegerDigits: 2})}.${Math.floor(diff % SEC).toLocaleString('en-US', {minimumIntegerDigits: 4, useGrouping: false})}`
console.log("humanDiff:", humanDiff)
// > humanDiff: 30:51:51.0111作为函数
function humanDiff (t1, t2) {
const diff = Math.max(t1,t2) - Math.min(t1,t2)
const SEC = 1000, MIN = 60 * SEC, HRS = 60 * MIN
const hrs = Math.floor(diff/HRS)
const min = Math.floor((diff%HRS)/MIN).toLocaleString('en-US', {minimumIntegerDigits: 2})
const sec = Math.floor((diff%MIN)/SEC).toLocaleString('en-US', {minimumIntegerDigits: 2})
const ms = Math.floor(diff % SEC).toLocaleString('en-US', {minimumIntegerDigits: 4, useGrouping: false})
return `${hrs}:${min}:${sec}.${ms}`
}
const t1 = new Date(1579876543210)
const t2 = new Date(1579987654321)
console.log("humanDiff(t1, t2):", humanDiff(t1, t2))
// > humanDiff: 30:51:51.0111解释
根据您的最大和最小可报告增量以及格式需求，调整 humanDiff：
const t1 = new Date(1579876543210) // Set your initial time (`t1`)
const t2 = new Date(1579986654321) // , conclusion time (`t2`), and
const diff = t2-t1 // calculate their difference in milliseconds
console.log(" t2:", t2.toISOString()) // > t2: 2020-01-25T21:27:34.321Z
console.log(" t1:", t1.toISOString()) // > t1: 2020-01-24T14:35:43.210Z
console.log(" diff:", diff) // > diff: 111111111
// Set your constant time values for easy readability
const SEC = 1000
const MIN = 60 * SEC
const HRS = 60 * MIN
/* For a given unit
1) disregard any previously relevant units, e.g. to calculate minutes, we can
disregard all hours & focus on only the remainder - `(diff%HRS)`
2) divide the remainder by the given unit, e.g. for minutes, `(diff%HRS)/MIN`
3) disregard any remainder, e.g. again for minutes, `Math.floor((diff%HRS)/MIN)`
NOTE: for your maximum unit (HRS in the examples below) you probably _don't_
want to disregard high values, e.g. If the difference is >24 hrs and something,
you should either include a DAYS value, or simply display 30 hrs */
let hrs = Math.floor(diff/HRS)
let min = Math.floor((diff%HRS)/MIN)
let sec = Math.floor((diff%MIN)/SEC)
let ms = Math.floor(diff % SEC) // just the remainder
// BUT ms IS NOT ACTUALLY CORRECT, see humanDiff_3 for the fix ;-)
let humanDiff_1 = `${hrs}:${min}:${sec}.${ms}`
console.log("humanDiff_1:", humanDiff_1)
// > humanDiff_1: 30:51:51.111
sec = Math.round((diff%MIN)/SEC) // can also just round the last unit
const humanDiff_2 = `${hrs} hrs ${min} mins & ${sec} secs`
console.log("humanDiff_2:", humanDiff_2)
// > humanDiff_2: 30 hrs 51 mins & 51 secs
/* To ensure a set number of digits, format the numbers with `toLocaleString`'s
`minimumIntegerDigits`, if more than 3 digits, also use its `useGrouping` */
hrs = Math.floor(diff/HRS)
min = Math.floor((diff%HRS)/MIN).toLocaleString('en-US', {minimumIntegerDigits: 2})
sec = Math.floor((diff%MIN)/SEC).toLocaleString('en-US', {minimumIntegerDigits: 2})
ms = Math.floor(diff % SEC).toLocaleString('en-US', {minimumIntegerDigits: 4, useGrouping: false})
const humanDiff_3 = `${hrs}:${min}:${sec}.${ms}`
console.log("humanDiff_3:", humanDiff_3)
// > humanDiff_3: 30:51:51.0111
// NOTE: milliseconds are now 4 digits- MetaSean
2
1感谢您提供这个函数，为什么SEC = 1000？ - Danish
SEC = 1000 只是因为1秒由1000毫秒组成；毫秒是Javascript中日期的基本值。 - MetaSean
4
尝试这个。
var dif = ( new Date("1970-1-1 " + end-time) - new Date("1970-1-1 " + start-time) ) / 1000 / 60 / 60;
- Abhishek Motiwale
2
这个解决方案适用于计算两个不同的军事时间之间的差异。
示例格式：开始时间 = 23:00 / 结束时间 = 02:30
function diff(start, end) {
start = start.split(":");
end = end.split(":");
if(Number(start[0]) > Number(end[0]) ) {
var num = Number(start[0])
var countTo = Number(end[0]);
var count = 0;
for (var i = 1; num != countTo;) {
num = num + i
if(num > 24) {
num = 0
}
count++
}
var hours = count - 1;
var startDate = new Date(0, 0, 0, start[0], start[1], 0);
var endDate = new Date(0, 0, 0, end[0], end[1], 0);
if(startDate.getMinutes() > endDate.getMinutes()) {
var hours = count - 2;
var diff = 60 - (startDate.getMinutes() - endDate.getMinutes());
} else {
var diff = endDate.getMinutes() - startDate.getMinutes();
}
var minutes = diff
} else {
var startDate = new Date(0, 0, 0, start[0], start[1], 0);
var endDate = new Date(0, 0, 0, end[0], end[1], 0);
var diff = endDate.getTime() - startDate.getTime();
var hours = Math.floor(diff / 1000 / 60 / 60);
diff -= hours * 1000 * 60 * 60;
var minutes = Math.floor(diff / 1000 / 60);
}
var returnValue = (hours < 9 ? "0" : "") + hours + ":" + (minutes < 9 ? "0" : "") + minutes
return returnValue;
}
- Joe
1
它不能在开始时间为5:30，结束时间为5:00时工作。返回0-1:30。 - Deepesh Thapa
1
这是已经提交过的版本的更新版。它是第二个版本。
function diff(start, end) {
start = start.split(":");
end = end.split(":");
var startDate = new Date(0, 0, 0, start[0], start[1], 0);
var endDate = new Date(0, 0, 0, end[0], end[1], 0);
var diff = endDate.getTime() - startDate.getTime();
var hours = Math.floor(diff / 1000 / 60 / 60);
diff -= hours * (1000 * 60 * 60);
var minutes = Math.floor(diff / 1000 / 60);
diff -= minutes * (1000 * 60);
var seconds = Math.floor(diff / 1000);
// If using time pickers with 24 hours format, add the below line get exact hours
if (hours < 0)
hours = hours + 24;
return (hours <= 9 ? "0" : "") + hours + ":" + (minutes <= 9 ? "0" : "") + minutes + (seconds<= 9 ? "0" : "") + seconds;
}
我的更新版本：
可以将日期转换为毫秒，并以此为基础进行计算，而不是拆分日期。
例子：年/月/周/日/小时/分钟/秒
- Casper0x413
1
您提供的秒数未能给我带来结果，请使用此处提供的更新函数，它将为您提供正确的秒数 - 作者：Dinesh J
function diff(start, end) {
start = start.split(":");
end = end.split(":");
var startDate = new Date(0, 0, 0, start[0], start[1],start[2], 0);
var endDate = new Date(0, 0, 0, end[0], end[1],end[2], 0);
var diff = endDate.getTime() - startDate.getTime();
var hours = Math.floor(diff / 1000 / 60 / 60);
diff -= hours * 1000 * 60 * 60;
var minutes = Math.floor(diff / 1000 / 60);
var seconds = Math.floor(diff / 1000)-120;
// If using time pickers with 24 hours format, add the below line get exact hours
if (hours < 0)
hours = hours + 24;
return (hours <= 9 ? "0" : "") + hours + ":" + (minutes <= 9 ? "0" : "") + minutes+ ":" + (seconds <= 9 ? "0" : "") + seconds;
}
- user8584085
1
这个工作几乎很好。现在使用这段代码来计算：23:50 - 00:10，看看你得到了什么。或者是23:30 - 01:30。那是一团糟。
因为在php中用另一种方式得到答案是：
所以，实际上您只需要4行代码即可获得结果。您可以仅花费几分钟或显示完整时间（例如差异为02:32）2小时32分钟。最重要的是：您仍然可以在24小时时钟中计算过夜，例如：开始时间为晚上11:50到01:00 AM（在24小时制中为23:50-01:00），因为在12小时模式下它仍然有效。
最重要的是：您不必格式化输入。您可以使用纯粹的2300作为23:00输入。此脚本将自动将文本字段输入转换为正确的格式。最后一个脚本使用带有method="get"的标准html表单，但您也可以将其转换为使用POST方法。
$date1 = strtotime($_POST['started']);
$date2 = strtotime($_POST['ended']);
$interval = $date2 - $date1;
$playedtime = $interval / 60;
但它仍然像你的一样工作。我猜也需要加入日期？
再次强调：我的艰苦研究和开发帮助了我。
if (isset($_POST['calculate'])) {
$d1 = $_POST['started'];
$d2 = $_POST['ended'];
if ($d2 < $d1) {
$date22 = date('Y-m-');
$date222 = date('d')-1;
$date2 = $date22."".$date222;
} else {
$date2 = date('Y-m-d');
}
$date1 = date('Y-m-d');
$start_time = strtotime($date2.' '.$d1);
$end_time = strtotime($date1.' '.$d2); // or use date('Y-m-d H:i:s') for current time
$playedtime = round(abs($start_time - $end_time) / 60,2);
}
这就是如何计算到第二天的时间。 //编辑。我最初把date1和date2搞反了。我需要减去1，因为这个计算只适用于下一天，而第一个日期是昨天。
经过改进和与我的朋友集思广益后，我们得出了以下结论：
$begin=mktime(substr($_GET["start"], 0,2),substr($_GET["start"], 2,2),0,1,2,2003);
$end=mktime(substr($_GET["end"], 0,2),substr($_GET["end"], 2,2),0,1,3,2003);
$outcome=($end-$begin)-date("Z");
$minutes=date("i",$outcome)+date("H",$outcome)*60; //Echo minutes only
$hours = date("H:i", $outcome); //Echo time in hours + minutes like 01:10 or something.
所以，实际上您只需要4行代码即可获得结果。您可以仅花费几分钟或显示完整时间（例如差异为02:32）2小时32分钟。最重要的是：您仍然可以在24小时时钟中计算过夜，例如：开始时间为晚上11:50到01:00 AM（在24小时制中为23:50-01:00），因为在12小时模式下它仍然有效。
最重要的是：您不必格式化输入。您可以使用纯粹的2300作为23:00输入。此脚本将自动将文本字段输入转换为正确的格式。最后一个脚本使用带有method="get"的标准html表单，但您也可以将其转换为使用POST方法。
- Germo
0
calTimeDifference(){
this.start = dailyattendance.InTime.split(":");
this.end = dailyattendance.OutTime.split(":");
var time1 = ((parseInt(this.start[0]) * 60) + parseInt(this.start[1]))
var time2 = ((parseInt(this.end[0]) * 60) + parseInt(this.end[1]));
var time3 = ((time2 - time1) / 60);
var timeHr = parseInt(""+time3);
var timeMin = ((time2 - time1) % 60);
}
- Sanket Parchande
0
TimeCount = function()
{
t++;
var ms = t;
if (ms == 99)
{
s++;
t = 0;
if ( s == 60)
{
m++;
s = 0;
}
}
Dis_ms = checkTime(ms);
Dis_s = checkTime(s);
Dis_m = checkTime(m);
document.getElementById("time_val").innerHTML = Dis_m + ":" + Dis_s+ ":" + Dis_ms;
}
function checkTime(i)
{
if (i<10) {
i = "0" + i;
}
return i;
} - Shanshana Samarajeewa
1
这段代码不完整 - 这是一个答案还是一个提问的尝试？ - barbsan
0
根据您允许输入的内容，这个程序可以工作。如果您想允许1am到1pm之间的时间，可能会有一些边界问题。
注意：此程序不使用日期对象或moment.js库。
function pad(num) {
return ("0"+num).slice(-2);
}
function diffTime(start,end) {
var s = start.split(":"), sMin = +s[1] + s[0]*60,
e = end.split(":"), eMin = +e[1] + e[0]*60,
diff = eMin-sMin;
if (diff<0) { sMin-=12*60; diff = eMin-sMin }
var h = Math.floor(diff / 60),
m = diff % 60;
return "" + pad(h) + ":" + pad(m);
}
document.getElementById('button').onclick=function() {
document.getElementById('delay').value=diffTime(
document.getElementById('timeOfCall').value,
document.getElementById('timeOfResponse').value
);
}<input type="time" id="timeOfCall">
<input type="time" id="timeOfResponse">
<button type="button" id="button">CLICK</button>
<input type="time" id="delay">- mplungjan
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