String linkPattern = "\\[[A-Za-z_0-9]+\\]";
String text = "[build]/directory/[something]/[build]/";
RegExp reg = RegExp.compile(linkPattern,"g");
MatchResult matchResult = reg.exec(text);
for (int i = 0; i < matchResult.getGroupCount(); i++) {
System.out.println("group" + i + "=" + matchResult.getGroup(i));
}
我正在尝试获取由方括号包裹的所有块,形成路径字符串: 但我只得到了group0="[build]",我想要的是: 1:“[build]”2:“[something]”3:“[build]”
编辑: 只是为了清晰起见,括号内的单词是用随机文本生成的。
public static String genText()
{
final int LENGTH = (int)(Math.random()*12)+4;
StringBuffer sb = new StringBuffer();
for (int x = 0; x < LENGTH; x++)
{
sb.append((char)((int)(Math.random() * 26) + 97));
}
String str = sb.toString();
str = str.substring(0,1).toUpperCase() + str.substring(1);
return str;
}
编辑 2: JDK工作正常,GWT RegExp出现了问题
已解决: Didier L的答案
String linkPattern = "\\[[A-Za-z_0-9]+\\]";
String result = "";
String text = "[build]/directory/[something]/[build]/";
RegExp reg = RegExp.compile(linkPattern,"g");
MatchResult matchResult = null;
while((matchResult=reg.exec(text)) != null){
if(matchResult.getGroupCount()==1)
System.out.println( matchResult.getGroup(0));
}
exec
直到它返回null
吗?因为它是全局的RegExp
,它将使用最后一个索引来确定从哪里开始。 - Didier L