Apache HttpClient 4.1 - 代理设置

Question

我想向服务器POST一些参数，但需要设置代理。你能帮我把我的代码中"设置代理"部分处理好吗？

HttpHost proxy = new HttpHost("xx.x.x.xx");

DefaultHttpClient httpclient = new DefaultHttpClient();

httpclient.getParams().setParameter("3128",proxy);


HttpPost httpost = new HttpPost(url);
List<NameValuePair> nvps = new ArrayList<NameValuePair>();

nvps.add(new BasicNameValuePair("aranan", song));

httpost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.UTF_8));

HttpResponse response = httpclient.execute(httpost);
HttpEntity entity = response.getEntity();
System.out.println("Request Handled?: " + response.getStatusLine());

in = entity.getContent();

httpclient.getConnectionManager().shutdown();

- Srpr

Answer 1

是的，我解决了自己的问题，这行代码

httpclient.getParams().setParameter("3128",proxy);

应该是这样的。

httpclient.getParams().setParameter(ConnRoutePNames.DEFAULT_PROXY,proxy);

下面是一个完整的Apache HttpClient 4.1设置代理的示例：

HttpHost proxy = new HttpHost("ip address",port number);
DefaultHttpClient httpclient = new DefaultHttpClient();
httpclient.getParams().setParameter(ConnRoutePNames.DEFAULT_PROXY,proxy);

HttpPost httpost = new HttpPost(url);
List<NameValuePair> nvps = new ArrayList<NameValuePair>();
nvps.add(new BasicNameValuePair("param name", param));
httpost.setEntity(new UrlEncodedFormEntity(nvps, HTTP.ISO_8859_1));
HttpResponse response = httpclient.execute(httpost);

HttpEntity entity = response.getEntity();
System.out.println("Request Handled?: " + response.getStatusLine());
InputStream in = entity.getContent();
httpclient.getConnectionManager().shutdown();

- Srpr

---

httpclient.getParams().setParameter(ConnRoutePNames.DEFAULT_PROXY,proxy);已经被弃用。 - Mazhar

HttpHost代理 = new HttpHost（“ IP地址”，端口号）; DefaultHttpClient httpclient = new DefaultHttpClient（）; httpclient.getParams（）。setParameter（ConnRoutePNames.DEFAULT_PROXY，proxy）; 在4.5.6上运行得很好。 - Yuri

Answer 2

非弃用的做法（在4.5.5版本中也适用）是：

HttpHost proxy = new HttpHost("proxy.com", 80, "http");
DefaultProxyRoutePlanner routePlanner = new DefaultProxyRoutePlanner(proxy);
CloseableHttpClient httpclient = HttpClients.custom()
                    .setRoutePlanner(routePlanner)
                    .build();

- Mazhar

---

你应该使用new HttpHost("proxy.com", 80, HttpHost.DEFAULT_SCHEME_NAME)或者new HttpHost("proxy.com", 80)。 - Wienczny

非常感谢，我对于Apache Commons Http和HttpComponents有些困惑，现在我可以同时使用它们了。 - Humoyun Ahmad

谢谢您提供的非废弃解决方案 :) - Talador12

Answer 3

这是我用来设置代理的快速方法：

import org.apache.http.HttpHost;
import org.apache.http.client.HttpClient;
import org.apache.http.impl.client.HttpClientBuilder;    
...
HttpHost proxy = new HttpHost("www.proxy.com", 8080, "http");
HttpClient httpClient = HttpClientBuilder.create().setProxy(proxy).build();

- Iwo Kucharski

Answer 4

当我使用apache httpclient v4.5.5时，发现HttpClient.getParams()在v4.3中已经被弃用，我们应该使用org.apache.http.client.config.RequestConfig代替。下面的代码示例说明了这一点：

 HttpHost target = new HttpHost("httpbin.org", 443, "https");
 HttpHost proxy = new HttpHost("127.0.0.1", 8080, "http");

 RequestConfig config = RequestConfig.custom()
     .setProxy(proxy)
     .build();
 HttpGet request = new HttpGet("/");
 request.setConfig(config);
 CloseableHttpResponse response = httpclient.execute(target, request);

- Allen