如何在Swift iOS中获取路由器的IP地址

3

你需要调用外部API获取公网IP和路由器IP。 - Anbu.Karthik
@Anbu.Karthik,请问你能解释一下我应该调用哪个外部API吗?我需要单独创建它们吗? - SandeepM
你应该检查以下网址:https://stackoverflow.com/questions/58503680/is-there-any-way-to-get-the-default-gateway-ip-on-ios-using-swift - the_exclusive
1个回答

1

您可以使用sysctl从路由表中获取默认网关的IP地址,但首先您应该定义所需的结构和常量,因为Darwin.net.route<route.h>未暴露给iOS SDK:

let RTAX_GATEWAY = 1
let RTAX_MAX = 8

public struct rt_metrics {
    public var rmx_locks: UInt32 /* Kernel leaves these values alone */
    public var rmx_mtu: UInt32 /* MTU for this path */
    public var rmx_hopcount: UInt32 /* max hops expected */
    public var rmx_expire: Int32 /* lifetime for route, e.g. redirect */
    public var rmx_recvpipe: UInt32 /* inbound delay-bandwidth product */
    public var rmx_sendpipe: UInt32 /* outbound delay-bandwidth product */
    public var rmx_ssthresh: UInt32 /* outbound gateway buffer limit */
    public var rmx_rtt: UInt32 /* estimated round trip time */
    public var rmx_rttvar: UInt32 /* estimated rtt variance */
    public var rmx_pksent: UInt32 /* packets sent using this route */
    public var rmx_state: UInt32 /* route state */
    public var rmx_filler: (UInt32, UInt32, UInt32) /* will be used for TCP's peer-MSS cache */
}

public struct rt_msghdr2 {
    public var rtm_msglen: u_short /* to skip over non-understood messages */
    public var rtm_version: u_char /* future binary compatibility */
    public var rtm_type: u_char /* message type */
    public var rtm_index: u_short /* index for associated ifp */
    public var rtm_flags: Int32 /* flags, incl. kern & message, e.g. DONE */
    public var rtm_addrs: Int32 /* bitmask identifying sockaddrs in msg */
    public var rtm_refcnt: Int32 /* reference count */
    public var rtm_parentflags: Int32 /* flags of the parent route */
    public var rtm_reserved: Int32 /* reserved field set to 0 */
    public var rtm_use: Int32 /* from rtentry */
    public var rtm_inits: UInt32 /* which metrics we are initializing */
    public var rtm_rmx: rt_metrics /* metrics themselves */
}

public func getDefaultGateway() -> String? {
    var name: [Int32] = [
        CTL_NET,
        PF_ROUTE,
        0,
        0,
        NET_RT_DUMP2,
        0
    ]
    let nameSize = u_int(name.count)
    
    var bufferSize = 0
    sysctl(&name, nameSize, nil, &bufferSize, nil, 0)
    
    let buffer = UnsafeMutablePointer<UInt8>.allocate(capacity: bufferSize)
    defer { buffer.deallocate() }
    buffer.initialize(repeating: 0, count: bufferSize)
    
    guard sysctl(&name, nameSize, buffer, &bufferSize, nil, 0) == 0 else { return nil }
    
    // Routes
    var rt = buffer
    let end = rt.advanced(by: bufferSize)
    while rt < end {
        let msg = rt.withMemoryRebound(to: rt_msghdr2.self, capacity: 1) { $0.pointee }
        
        // Addresses
        var addr = rt.advanced(by: MemoryLayout<rt_msghdr2>.stride)
        for i in 0..<RTAX_MAX {
            if (msg.rtm_addrs & (1 << i)) != 0 && i == RTAX_GATEWAY {
                let si = addr.withMemoryRebound(to: sockaddr_in.self, capacity: 1) { $0.pointee }
                if si.sin_addr.s_addr == INADDR_ANY {
                    return "default"
                }
                else {
                    return String(cString: inet_ntoa(si.sin_addr), encoding: .ascii)
                }
            }
            
            let sa = addr.withMemoryRebound(to: sockaddr.self, capacity: 1) { $0.pointee }
            addr = addr.advanced(by: Int(sa.sa_len))
        }
        
        rt = rt.advanced(by: Int(msg.rtm_msglen))
    }
    
    return nil
}

// How to use
if let ip = getDefaultGateway() {
    print(ip)
}
// Prints: 192.168.1.1



如果网关是0.0.0.0,我们能否在iOS中获取连接的接入点的IP地址? - Akshada-Systematix
我们尝试了这段代码,得到的是连接接入点的网关IP地址,在我的情况下是0.0.0.0。但我们想要连接接入点的IP地址而不是它的网关IP。你能帮忙吗? - Akshada-Systematix
我该如何在iOS Swift中获取DHCP服务器的IP地址? - Akshada-Systematix
@Akshada-Systematix 我的示例展示了如何访问您的路由表并获取有关默认网关的信息。路由表包含所有已知路由,例如主机、子网和默认路由,您可以通过分析其标志从列表中获取所需路由。FreeBSD 网关和路由 - https://docs.freebsd.org/en/books/handbook/advanced-networking/#network-routing - iUrii

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