将这个渐变图片转换为CSS渐变。

Question

将这个渐变图片转换为CSS渐变。

4

我正在尝试使用CSS来生成下面的渐变图像。然而，我在对齐方面遇到了困难。您会注意到在我的代码片段中出现了问题。我尝试绝对定位它们，但这只会使情况更糟。

.gradients {
  position: relative;
  width: 100%;
}

.gradients div {
  height: 40px;
}

.bottom-gradient {
  -ms-transform: rotate(0.6deg);
  -webkit-transform: rotate(0.6deg);
  transform: rotate(0.6deg);
  background: -moz-linear-gradient(left, rgba(37, 52, 47, 0.9) 0%, rgba(3, 95, 26, 0.9) 100%);
  background: -webkit-gradient(linear, left top, right top, color-stop(0%, rgba(37, 52, 47, 0.9)), color-stop(100%, rgba(3, 95, 26, 0.9)));
  background: -webkit-linear-gradient(left, rgba(37, 52, 47, 0.9) 0%, rgba(3, 95, 26, 0.9) 100%);
  background: -o-linear-gradient(left, rgba(37, 52, 47, 0.9) 0%, rgba(3, 95, 26, 0.9) 100%);
  background: -ms-linear-gradient(left, rgba(37, 52, 47, 0.9) 0%, rgba(3, 95, 26, 0.9) 100%);
  background: linear-gradient(to right, rgba(37, 52, 47, 0.9) 0%, rgba(3, 95, 26, 0.9) 100%);
  filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#80414c46', endColorstr='#80035f1a', GradientType=1);
}

.top-gradient {
  -ms-transform: rotate(0.6deg);
  -webkit-transform: rotate(0.6deg);
  transform: rotate(0.10deg);
  background: -moz-linear-gradient(left, rgba(3, 95, 26, 0.9) 0%, rgba(37, 52, 47, 0.9) 100%);
  background: -webkit-gradient(linear, left top, right top, color-stop(0%, rgba(3, 95, 26, 0.9)), color-stop(100%, rgba(37, 52, 47, 0.9)));
  background: -webkit-linear-gradient(left, rgba(3, 95, 26, 0.9) 0%, rgba(37, 52, 47, 0.9) 100%);
  background: -o-linear-gradient(left, rgba(3, 95, 26, 0.9) 0%, rgba(37, 52, 47, 0.9) 100%);
  background: -ms-linear-gradient(left, rgba(3, 95, 26, 0.9) 0%, rgba(37, 52, 47, 0.9) 100%);
  background: linear-gradient(to right, rgba(3, 95, 26, 0.9) 0%, rgba(37, 52, 47, 0.9) 100%);
  filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#80035f1a', endColorstr='#80414c46', GradientType=1);
}

<div class="gradients">
  <div class="top-gradient"></div>
  <div class="bottom-gradient"></div>
</div>

- imvain2

2个回答

0

您可以仅使用伪元素并定义一次渐变来优化您的代码。

.gradients {
  position: relative;
  height: 40px;
  margin:40px 0;
}
.gradients:before,
.gradients:after{
  content:"";
  position:absolute;
  top:0;
  left:0;
  right:0;
  bottom:0;
  transform: rotate(2deg);
  background: linear-gradient(to right, rgba(37, 52, 47, 0.9), rgba(3, 95, 26, 0.9));
}
.gradients:after {
  /* since it's the same gradient in the other direction, you can simply make a mirror image of it*/
  transform:scaleX(-1) rotate(2deg);
}

<div class="gradients">
</div>

您也可以考虑使用skew()而不是rotate来获得不同的效果，可能更接近您想要的效果。请注意边缘的差异：

.gradients {
  position: relative;
  height: 40px;
  margin:40px 0;
}
.gradients:before,
.gradients:after{
  content:"";
  position:absolute;
  top:0;
  left:0;
  right:0;
  bottom:0;
  transform: skewY(2deg);
  background: linear-gradient(to right, rgba(37, 52, 47, 0.9), rgba(3, 95, 26, 0.9));
}
.gradients:after {
  /* since it's the same gradient in the other direction, you can simply make a mirror image of it*/
  transform:scaleX(-1) skewY(2deg);
}

<div class="gradients">
</div>

我还怀疑你想要一些具有响应性的东西，这意味着当你调整窗口大小时，两个渐变之间的距离不应该改变（这不适用于上述解决方案）。为了做到这一点，这里有一个依赖于SVG和背景的想法：

.gradients {
  position: relative;
  height: 80px;
  margin:40px 0;
  background-image: url('data:image/svg+xml;charset=UTF-8,<svg version="1.1"  xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" x="0px" y="0px" preserveAspectRatio="none" viewBox="0 0 25 30" ><defs><linearGradient id="one" ><stop offset="0%" stop-color="rgba(37, 52, 47, 0.9)"/><stop offset="100%" stop-color="rgba(3, 95, 26, 0.9)" /></linearGradient><linearGradient id="two" ><stop offset="0%" stop-color="rgba(3, 95, 26, 0.9)" /><stop offset="100%" stop-color="rgba(37, 52, 47, 0.9)"/></linearGradient></defs><polygon points="25,7 25,25 0,18 0,0" fill="url(%23one)"/><polygon points="25,0 25,18 0,25 0,7" fill="url(%23two)"/></svg>');
  background-size:100%;
}

<div class="gradients">
</div>

这里是SVG代码，使用不同的颜色进行扩展以更好地理解：

svg {
  width:100%;
  height:100px;
}

<svg version="1.1" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" x="0px" y="0px" preserveAspectRatio="none" viewBox="0 0 25 30">
  <defs>
    <linearGradient id="one" >
        <stop offset="0%" stop-color="blue"/>
        <stop offset="100%" stop-color="red" />
   </linearGradient>
   <linearGradient id="two" >
        <stop offset="0%" stop-color="yellow" />
        <stop offset="100%" stop-color="purple"/>
  </linearGradient>
 </defs>
 <!-- update the value 7 and 18 by keeping it the same between both polygon -->
 <polygon points="25,7 25,25 0, 18 0, 0" fill="url(#one)"/>
 <polygon points="0, 7 0, 25 25,18 25,0" fill="url(#two)"/>
 
</svg>

- Temani Afif

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- Tyler Roper · Accepted Answer

position: absolute或负margin都可以使用，但需要硬编码的值。更灵活的选择是在.bottom-gradient中添加transform: translateY(-100%)。

由于此元素已经有一个transform: rotate(0.6deg)，因此您只需将translateY附加到它即可：

.bottom-gradient { transform: rotate(0.6deg) translateY(-100%) }

为了更好地复制图像，我还做出了以下更改：

将渐变的旋转改为1度和-1度。
将高度改为16px；

.gradients {
  position: relative;
  width: 100%;
}

.gradients div {
  height: 16px;
}

.bottom-gradient {
  -ms-transform: rotate(-1deg) translateY(-100%);
  -webkit-transform: rotate(-1deg) translateY(-100%);
  transform: rotate(-1deg) translateY(-100%);
  background: -moz-linear-gradient(left, rgba(37, 52, 47, 0.9) 0%, rgba(3, 95, 26, 0.9) 100%);
  background: -webkit-gradient(linear, left top, right top, color-stop(0%, rgba(37, 52, 47, 0.9)), color-stop(100%, rgba(3, 95, 26, 0.9)));
  background: -webkit-linear-gradient(left, rgba(37, 52, 47, 0.9) 0%, rgba(3, 95, 26, 0.9) 100%);
  background: -o-linear-gradient(left, rgba(37, 52, 47, 0.9) 0%, rgba(3, 95, 26, 0.9) 100%);
  background: -ms-linear-gradient(left, rgba(37, 52, 47, 0.9) 0%, rgba(3, 95, 26, 0.9) 100%);
  background: linear-gradient(to right, rgba(37, 52, 47, 0.9) 0%, rgba(3, 95, 26, 0.9) 100%);
  filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#80414c46', endColorstr='#80035f1a', GradientType=1);
}

.top-gradient {
  -ms-transform: rotate(1deg);
  -webkit-transform: rotate(1deg);
  transform: rotate(1deg);
  background: -moz-linear-gradient(left, rgba(3, 95, 26, 0.9) 0%, rgba(37, 52, 47, 0.9) 100%);
  background: -webkit-gradient(linear, left top, right top, color-stop(0%, rgba(3, 95, 26, 0.9)), color-stop(100%, rgba(37, 52, 47, 0.9)));
  background: -webkit-linear-gradient(left, rgba(3, 95, 26, 0.9) 0%, rgba(37, 52, 47, 0.9) 100%);
  background: -o-linear-gradient(left, rgba(3, 95, 26, 0.9) 0%, rgba(37, 52, 47, 0.9) 100%);
  background: -ms-linear-gradient(left, rgba(3, 95, 26, 0.9) 0%, rgba(37, 52, 47, 0.9) 100%);
  background: linear-gradient(to right, rgba(3, 95, 26, 0.9) 0%, rgba(37, 52, 47, 0.9) 100%);
  filter: progid:DXImageTransform.Microsoft.gradient( startColorstr='#80035f1a', endColorstr='#80414c46', GradientType=1);
}

<div class="gradients">
  <div class="top-gradient"></div>
  <div class="bottom-gradient"></div>
</div>