我的问题是对称解密,不是非对称解密。正确的答案在这里: Java中仅使用密语解密PGP加密文件
我使用gpg加密"hello":
[root@shc-sma-cd13 opt]# echo "hello" | gpg --symmetric --armor --cipher-algo AES256 --passphrase "2R79P7z5f8350VEp" --batch
-----BEGIN PGP MESSAGE-----
Version: GnuPG v2.0.22 (GNU/Linux)
jA0ECQMC1XpaSrXhBAfU0jsBXw817k4k4iT++AGV8MUev4/gKkuIwAW2VaJsEANa
+0ZuqZgFp/8N7AndRhyNj5WGcloQQkLkwvIV3Q==
=GwQi
-----END PGP MESSAGE-----
我使用Java来解密字符串:
public class AESUtils1 {
private static final String KEY_VAL = "2R79P7z5f8350VEp";
public static String AESDecode(String content) {
try {
SecretKey key = new SecretKeySpec(KEY_VAL.getBytes(), "AES");
Cipher cipher = Cipher.getInstance("AES");
cipher.init(Cipher.DECRYPT_MODE, key);
byte[] byte_content = new BASE64Decoder().decodeBuffer(content);
byte[] byte_decode = cipher.doFinal(byte_content);
String AES_decode = new String(byte_decode, "utf-8");
return AES_decode;
} catch (NoSuchAlgorithmException e) {
e.printStackTrace();
} catch (NoSuchPaddingException e) {
e.printStackTrace();
} catch (InvalidKeyException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
} catch (IllegalBlockSizeException e) {
e.printStackTrace();
} catch (BadPaddingException e) {
e.printStackTrace();
}
//如果有错就返加nulll
return null;
}
public static void main(String[] args) {
String encryptString = "jA0ECQMC1XpaSrXhBAfU0jsBXw817k4k4iT++AGV8MUev4/gKkuIwAW2VaJsEANa\n" +
" +0ZuqZgFp/8N7AndRhyNj5WGcloQQkLkwvIV3Q==\n" +
" =GwQi";
String decryptString = AESDecode(encryptString);
System.out.println("decryptString: " + decryptString);
}
}
但是它失败了并显示错误信息:
javax.crypto.IllegalBlockSizeException: Input length must be multiple of 16 when decrypting with padded cipher
at com.sun.crypto.provider.CipherCore.doFinal(CipherCore.java:936)
at com.sun.crypto.provider.CipherCore.doFinal(CipherCore.java:847)
at com.sun.crypto.provider.AESCipher.engineDoFinal(AESCipher.java:446)
at javax.crypto.Cipher.doFinal(Cipher.java:2164)
at com.hpe.itsma.itsmaInstaller.AESUtils1.AESDecode(AESUtils1.java:33)
at com.hpe.itsma.itsmaInstaller.AESUtils1.main(AESUtils1.java:57)
decryptString: null
我很好奇,gpg生成的加密字符串在Java中该如何使用。使用Java加密“hello”的输出结果与gpg不同。还有一个有趣的问题是,每次运行命令echo "hello" | gpg --symmetric --armor --cipher-algo AES256 --passphrase "2R79P7z5f8350VEp" --batch
,结果都是不同的。是否可能解密由gpg加密的字符串?或者我使用gpg的方式有误?
echo "hello" | gpg --symmetric --armor --cipher-algo AES256 --passphrase "2R79P7z5f8350VEp" --batch
结果总是不同的。 - Cain