我有这本课程教材:
@Entity
@Table(name = "books")
@XmlRootElement
@XmlAccessorType(XmlAccessType.FIELD)
@XmlType
public class Book {
@Id
@XmlAttribute
private String isbn;
private String title;
private String authors;
private int year;
@OneToMany(mappedBy="reservedBook")
private List<Reservation> bookReservations;
//Getters, setters, addReservation, remove Reservation
......................
}
然后,我有一个预订类。
@Entity
@Table(name = "reservations")
@XmlRootElement
public class Reservation {
private String username;
private String isbn;
@Temporal(TemporalType.DATE)
private Date date;
@ManyToOne
@JoinColumn(name = "isbn")
private Book reservedBook;
@ManyToOne
@JoinColumn(name = "username")
private User userWhoReserved;
//Getters and setters
...........
}
在资源类中,我尝试像这样获取特定的书籍:
@GET
@Path("/{isbn}")
@Produces(MediaType.TEXT_XML)
public Book getBookByIsbn(@PathParam("isbn") String isbn) {
Book book = entityManager.find(Book.class, isbn);
if (book != null) {
return book;
}
}
现在,它不序列化字段List bookReservations。我尝试了很多在网上找到的想法,比如用@XmlElement注释列表的getter或在其他地方使用其他注释(我现在不记得了),但都没用。
编辑:这就是响应的样子:
<book isbn="3333333333">
<title>Mere Christianity</title>
<authors>C. S. Lewis</authors>
<year>2000</year>
</book>
但我也想显示保留内容。
有什么解决方案吗? 谢谢! Sorin