如何在安卓设备上使用.pls文件进行流媒体播放?

7

我想在我的安卓应用程序上使用这个url http://playerservices.streamtheworld.com/pls/VIRGINRADIO_DUBAIAAC.pls 播放一个 .pls 文件,但是我知道直接使用MediaPlayer无法播放 .pls 文件。所以我使用了一个Pls解析器来解析这个文件,并将每个url设置为媒体播放器,但是它不起作用。同时显示错误error (1, -2147483648)

public class PlayListParser {

    private BufferedReader reader;

    public PlayListParser(String url) {
        try {
            URL plsFileUrl = new URL(url.trim());
            URLConnection urlConnection = plsFileUrl.openConnection();
           // InputStream input = new BufferedInputStream(urlConnection.openStream());
            InputStream iStream = urlConnection.getInputStream();
            this.reader = new BufferedReader(new InputStreamReader(iStream));
            // this.reader = new BufferedReader(new FileReader(file), 1024);
        } catch (MalformedURLException e) {
            Log.e("PlayListParser", "Got MalformedURLException  = " + e.getMessage());
        } catch (IOException e) {
            Log.e("PlayListParser", "Got  IOException = " + e.getMessage());
        }
    }

    public List<String> getUrls() {
        LinkedList<String> urls = new LinkedList<String>();
        while (true) {
            try {
                String line = reader.readLine();
                if (line == null) {
                    break;
                }
                String url = parseLine(line);
                if (url != null && !url.equals("")) {
                    urls.add(url);
                }
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
        return urls;
    }

    private String parseLine(String line) {
        if (line == null) {
            return null;
        }
        String trimmed = line.trim();
        if (trimmed.indexOf("http") >= 0) {
            return trimmed.substring(trimmed.indexOf("http"));
        }
        return "";
    }
}


PlayListParser playListParser = new PlayListParser(URL_PLS_STREAMING);
List<String > playList = playListParser.getUrls();
if(playList != null && ! playList.isEmpty()){
    for(String url : playList){
        MediaPlayer mediaPlayer = new MediaPlayer();
        try {
        mediaPlayer.setDataSource(playList.get(0));//"http://stream2.streamq.net:8020/");
        mediaPlayer.setAudioStreamType(AudioManager.STREAM_MUSIC);
        mediaPlayer.prepareAsync();
        mediaPlayer.setOnPreparedListener(new OnPreparedListener() {

            @Override
            public void onPrepared(MediaPlayer mp) {
                mp.start();

            }
        });
        //mediaPlayer.prepare();
        } catch (IllegalArgumentException e) {
        Log.e("MainActivity","Got IllegalArgumentException = " + e.getMessage());

        } catch (IllegalStateException e) {
        Log.e("MainActivity","Got IllegalStateException = " + e.getMessage());

        } catch (IOException e) {
        Log.e("MainActivity","Got IOException = " + e.getMessage());

        }
    }
}

我该如何播放这个 .pls 文件?我找不到一个好的参考资料。另外,我想播放、暂停和倒回这些文件。提前感谢您的帮助。

展示一下你处理 pls 文件的代码。 - Squonk
1个回答

7

从.pls文件获取URL

此操作将返回类似http://stream2.streamq.net:8020的URL。

package com.direct.radio.global;

import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
import java.net.MalformedURLException;
import java.net.URL;
import java.net.URLConnection;
import java.util.LinkedList;
import android.content.Context;
import android.util.Log;

public class GetStreamingUrl {

private static String LOGTAG = "GetStreamingUrl";
private Context mContext;

public GetStreamingUrl(Context context) {
    Log.i(LOGTAG, "call to constructor");
    this.mContext = context;

}

public LinkedList<String> getStreamingUrl(String url) {

    Log.i(LOGTAG, "get streaming url");
    final BufferedReader br;
    String murl = null;
    LinkedList<String> murls = null;
    try {
        URLConnection mUrl = new URL(url).openConnection();
        br = new BufferedReader(
                new InputStreamReader(mUrl.getInputStream()));
        murls = new LinkedList<String>();
        while (true) {
            try {
                String line = br.readLine();

                if (line == null) {
                    break;
                }
                murl = parseLine(line);
                if (murl != null && !murl.equals("")) {
                    murls.add(murl);

                }
            } catch (IOException e) {
                e.printStackTrace();
            }
        }
    } catch (MalformedURLException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    } catch (IOException e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
    Log.i(LOGTAG, "url to stream :" + murl);
    return murls;
}

private String parseLine(String line) {
    if (line == null) {
        return null;
    }
    String trimmed = line.trim();
    if (trimmed.indexOf("http") >= 0) {
        return trimmed.substring(trimmed.indexOf("http"));
    }
    return "";
        }
  } 

Activity_Player.java 或 Service_Player.java

您可以根据需要编写此代码,定义此方法。

LinkedList<String> urls;

private LinkedList<String> fGetPlayableUrl(String mPls) {
    GetStreamingUrl oGetStreamingUrl = new GetStreamingUrl(Activity_Splash.this);
    urls = oGetStreamingUrl.getStreamingUrl(mPls);
    return urls;
}

在这里,fGetPlayableUrl(String mPls) 传递了 .pls URL 。现在你有一个流媒体 URL。

MediaPlayer  mMediaPlayer = new MediaPlayer();

现在,将URL传递给

mMediaPlayer.setDataSource(urls.toString());
mMediaPlayer.prepareAsync();
mMediaPlayer.start();

mMediaPlayer.setDataSource(""),这里的URL是PLS文件的URL还是解析后的PLS文件中的URL? - Devu Soman
这意味着从已解析的 pls 文件中获取 URL,就像我的代码中一样。但是对我来说它不起作用。显示异常 SntpClient:请求时间失败:java.net.SocketException:协议不支持地址族。 - Devu Soman
@Devu Soman,你实现了这个 .pls 任务吗?我正在寻找同样的解决方案,但还没有找到。请帮帮我。 - Geet taunk
@Geettaunk,有什么问题吗? - Ronak Mehta
@Ann,我已经测试了这段代码,没有发现任何错误。 - Ronak Mehta
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