Django基于类的视图-使用两个模型表单的UpdateView-一个提交

Question

我有一个用户列表页面，并希望能够单击链接来更新其个人资料。当单击“更新”时，我应该能够在单个页面中使用单个提交按钮编辑用户名、名字、电子邮件、电话号码、部门等信息。我通过使用两个表单来实现这一点，一个用于用户，另一个用于额外信息。ListView、DeleteView和CreateView可以很好地使用这两个表单，但UpdateView不能。我无法使用初始数据实例化这两个表单。

问题是：如何使用数据实例化这两个表单？重写self.object？get_form_kwargs？什么是最优雅的解决方案？

以下是UpdateView类。我不是要求“复制粘贴”解决方案，而是帮我指明正确的方向。

谢谢。

Paul

电话号码、部门定义在名为Employee的模型中。

class Employee(models.Model):
    user = models.OneToOneField(User)
    phone_number = models.CharField(max_length=13, null=True)
    department = models.CharField(max_length=100)

模板是：

{% extends "baseadmin.html" %}
{% load crispy_forms_tags %}

{% block content %}
<h4>Edit a user</h4>
<form action="" method="post" class="form-horizontal">
    <legend>Edit a user</legend>
    {% crispy form %}
    {% crispy form2 %}
    <div class="form-actions">
        <input type="submit" class="btn btn-primary" value="Save">
            <a href="{% url 'client_list' %}" class="btn">Cancel</a>
    </div>
</form>
{% endblock content %}

视图类是：

class ClientUpdateView(UpdateView):
    model = User
    form_class = ClientsUserForm
    second_form_class = ClientsForm
    template_name = 'admin/client_update.html'

    def get_context_data(self, **kwargs):
        context = super(ClientUpdateView, self).get_context_data(**kwargs)
        context['active_client'] = True
        if 'form' not in context:
            context['form'] = self.form_class(self.request.GET)
        if 'form2' not in context:
            context['form2'] = self.second_form_class(self.request.GET)
        context['active_client'] = True
        return context

    def get(self, request, *args, **kwargs):
        super(ClientUpdateView, self).get(request, *args, **kwargs)
        form = self.form_class
        form2 = self.second_form_class
        return self.render_to_response(self.get_context_data(
            object=self.object, form=form, form2=form2))

    def post(self, request, *args, **kwargs):
        self.object = self.get_object()
        form = self.form_class(request.POST)
        form2 = self.second_form_class(request.POST)

        if form.is_valid() and form2.is_valid():
            userdata = form.save(commit=False)
            # used to set the password, but no longer necesarry
            userdata.save()
            employeedata = form2.save(commit=False)
            employeedata.user = userdata
            employeedata.save()
            messages.success(self.request, 'Settings saved successfully')
            return HttpResponseRedirect(self.get_success_url())
        else:
            return self.render_to_response(
              self.get_context_data(form=form, form2=form2))

    def get_success_url(self):
        return reverse('client_list')

- PPiscuc

---

UpdateView 对我来说没有更新，它只是转到 success_url。 - AnonymousUser

Answer 1

如果需要从现有模型实例化表单，则可以使用“instance” kwarg进行实例化。例如：

context['form'] = self.form_class(self.request.GET, instance=request.user)

- kdb

Answer 2

尝试停用 get_content_data 表单构造函数中的 self.request.get，并使用 "object" 变量。使用该 get 会重新初始化构造函数，更多信息请参见 this link。

我的代码：

 context['form'] = self.form_class(instance=self.object)

- Rafael GB

---

仍然是一样的。 - AnonymousUser

Answer 3

摒弃get方法，您不需要重写它。并在原地应用以下更改：

class ClientUpdateView(UpdateView):
       model = Employee # You can access the user by the profile, but not the 
       # oposit 
       form_class = ClientsForm
       second_form_class = ClientsUserForm
       template_name = 'admin/client_update.html'
      
       # def get(self, request, *args, **kwargs):
       # get rid off

       def get_context_data(self, **kwargs):
           kwargs['active_client'] = True
           if 'form' not in kwargs:
              kwargs['form'] = self.form_class(instance=self.get_object())
           if 'form2' not in kwargs:
              kwargst['form2'] = \ 
          self.second_form_class(instance=self.get_object().user)
          return super(ClientUpdateView, self).get_context_data(**kwargs)

       def post(self, request, *args, **kwargs): 
           ...

- Iaggo Capitanio