我已经编写了以下代码,我也能够获得JSON响应,但是JSON的类型是“AnyObject”,我无法将其转换为数组以便我可以使用它。
Alamofire.request(.POST, "MY URL", parameters:parameters, encoding: .JSON) .responseJSON
{
(request, response, JSON, error) in
println(JSON?)
}
对于Swift 2.0和Alamofire 3.0,答案应该更像这样:
Alamofire.request(.POST, url, parameters: parameters, encoding:.JSON).responseJSON
{ response in switch response.result {
case .Success(let JSON):
print("Success with JSON: \(JSON)")
let response = JSON as! NSDictionary
//example if there is an id
let userId = response.objectForKey("id")!
case .Failure(let error):
print("Request failed with error: \(error)")
}
}
针对Alamofire 4.0和Swift 3.0的更新:
Alamofire.request(url, method: .post, parameters: parameters, encoding: JSONEncoding.default)
.responseJSON { response in
print(response)
//to get status code
if let status = response.response?.statusCode {
switch(status){
case 201:
print("example success")
default:
print("error with response status: \(status)")
}
}
//to get JSON return value
if let result = response.result.value {
let JSON = result as! NSDictionary
print(JSON)
}
}
NSDictionary
,而应该使用Swift字典。 - rmaddy如上所述,您可以使用SwiftyJSON库并像我下面所做的那样获取您的值
Alamofire.request(.POST, "MY URL", parameters:parameters, encoding: .JSON) .responseJSON
{
(request, response, data, error) in
var json = JSON(data: data!)
println(json)
println(json["productList"][1])
}
我的JSON产品列表,由脚本返回
{ "productList" :[
{"productName" : "PIZZA","id" : "1","productRate" : "120.00","productDescription" : "PIZZA AT 120Rs","productImage" : "uploads\/pizza.jpeg"},
{"productName" : "BURGER","id" : "2","productRate" : "100.00","productDescription" : "BURGER AT Rs 100","productImage" : "uploads/Burgers.jpg"}
]
}
输出:
{
"productName" : "BURGER",
"id" : "2",
"productRate" : "100.00",
"productDescription" : "BURGER AT Rs 100",
"productImage" : "uploads/Burgers.jpg"
}
Swift 3,Alamofire 4.4和SwiftyJSON:
Alamofire.request(url, method: .get)
.responseJSON { response in
if response.data != nil {
let json = JSON(data: response.data!)
let name = json["people"][0]["name"].string
if name != nil {
print(name!)
}
}
}
这将解析此JSON输入:
{
people: [
{ name: 'John' },
{ name: 'Dave' }
]
}
JSON()
转换的必要:https://github.com/SwiftyJSON/Alamofire-SwiftyJSON - Robin Macharg我在 GitHub 找到了关于 Swift2 的答案。
https://github.com/Alamofire/Alamofire/issues/641
Alamofire.request(.GET, URLString, parameters: ["foo": "bar"])
.responseJSON { request, response, result in
switch result {
case .Success(let JSON):
print("Success with JSON: \(JSON)")
case .Failure(let data, let error):
print("Request failed with error: \(error)")
if let data = data {
print("Response data: \(NSString(data: data, encoding: NSUTF8StringEncoding)!)")
}
}
}
我既不是JSON专家,也不是Swift专家,但以下内容对我有效。 :) 我从我的当前应用程序中提取了代码,并仅将"MyLog"更改为"println",并使用空格进行缩进以将其显示为代码块(希望我没有破坏它)。
func getServerCourseVersion(){
Alamofire.request(.GET,"\(PUBLIC_URL)/vtcver.php")
.responseJSON { (_,_, JSON, _) in
if let jsonResult = JSON as? Array<Dictionary<String,String>> {
let courseName = jsonResult[0]["courseName"]
let courseVersion = jsonResult[0]["courseVersion"]
let courseZipFile = jsonResult[0]["courseZipFile"]
println("JSON: courseName: \(courseName)")
println("JSON: courseVersion: \(courseVersion)")
println("JSON: courseZipFile: \(courseZipFile)")
}
}
}
希望这可以帮助到您。
编辑:
供参考,以下是我的 PHP 脚本返回的内容:
[{"courseName": "Training Title","courseVersion": "1.01","courseZipFile": "101/files.zip"}]
class User: Decodable {
var name: String
var email: String
var token: String
enum CodingKeys: String, CodingKey {
case name
case email
case token
}
public required init(from decoder: Decoder) throws {
let container = try decoder.container(keyedBy: CodingKeys.self)
self.name = try container.decode(String.self, forKey: .name)
self.email = try container.decode(String.self, forKey: .email)
self.token = try container.decode(String.self, forKey: .token)
}
}
Alamofire.request("url.endpoint/path", method: .get, parameters: params, encoding: URLEncoding.queryString, headers: nil)
.validate()
.responseJSON { response in
switch (response.result) {
case .success( _):
do {
let users = try JSONDecoder().decode([User].self, from: response.data!)
print(users)
} catch let error as NSError {
print("Failed to load: \(error.localizedDescription)")
}
case .failure(let error):
print("Request error: \(error.localizedDescription)")
}
responseDecodable
而不是responseJSON
。 - Jon ShierSwift 3
pod 'Alamofire', '~> 4.4'
pod 'SwiftyJSON'
File json format:
{
"codeAd": {
"dateExpire": "2017/12/11",
"codeRemoveAd":"1231243134"
}
}
import Alamofire
import SwiftyJSON
private func downloadJson() {
Alamofire.request("https://yourlinkdownloadjson/abc").responseJSON { response in
debugPrint(response)
if let json = response.data {
let data = JSON(data: json)
print("data\(data["codeAd"]["dateExpire"])")
print("data\(data["codeAd"]["codeRemoveAd"])")
}
}
}
此项目使用Xcode 10.1和Swift 4构建
完美组合"Alamofire"(4.8.1) 和 "SwiftyJSON"(4.2.0),首先您需要安装这两个pod
pod 'Alamofire'
和pod 'SwiftyJSON'
服务器响应以JSON格式返回:
{
"args": {},
"headers": {
"Accept": "*/*",
"Accept-Encoding": "gzip;q=1.0, compress;q=0.5",
"Accept-Language": "en;q=1.0",
"Host": "httpbin.org",
"User-Agent": "AlamoFire TEST/1.0 (com.ighost.AlamoFire-TEST; build:1; iOS 12.1.0) Alamofire/4.8.1"
},
"origin": "200.55.140.181, 200.55.140.181",
"url": "https://httpbin.org/get"
}
Alamofire.request("https://httpbin.org/get").validate().responseJSON { response in
switch response.result {
case .success:
print("Validation Successful)")
if let json = response.data {
do{
let data = try JSON(data: json)
let str = data["headers"]["Host"]
print("DATA PARSED: \(str)")
}
catch{
print("JSON Error")
}
}
case .failure(let error):
print(error)
}
}
保持冷静,愉快地编写代码
我找到了一种方法,可以将Alamofire responseJSON闭包中的response.result.value转换为JSON格式,以便在我的应用程序中使用。
我正在使用Alamofire 3和Swift 2.2。
这是我使用的代码:
Alamofire.request(.POST, requestString,
parameters: parameters,
encoding: .JSON,
headers: headers).validate(statusCode: 200..<303)
.validate(contentType: ["application/json"])
.responseJSON { (response) in
NSLog("response = \(response)")
switch response.result {
case .Success:
guard let resultValue = response.result.value else {
NSLog("Result value in response is nil")
completionHandler(response: nil)
return
}
let responseJSON = JSON(resultValue)
// I do any processing this function needs to do with the JSON here
// Here I call a completionHandler I wrote for the success case
break
case .Failure(let error):
NSLog("Error result: \(error)")
// Here I call a completionHandler I wrote for the failure case
return
}
我通常使用Gloss库在iOS中进行JSON的序列化或反序列化。例如,我有这样的JSON:
{"ABDC":[{"AB":"qwerty","CD":"uiop"}],[{"AB":"12334","CD":"asdf"}]}
首先,我在Gloss结构中对JSON数组进行建模:
Struct Struct_Name: Decodable {
let IJ: String?
let KL: String?
init?(json: JSON){
self.IJ = "AB" <~~ json
self.KL = "CD" <~~ json
}
}
然后在Alamofire的responseJSON中,我执行以下操作:
Alamofire.request(url, method: .get, paramters: parametersURL).validate(contentType: ["application/json"]).responseJSON{ response in
switch response.result{
case .success (let data):
guard let value = data as? JSON,
let eventsArrayJSON = value["ABDC"] as? [JSON]
else { fatalError() }
let struct_name = [Struct_Name].from(jsonArray: eventsArrayJSON)//the JSON deserialization is done here, after this line you can do anything with your JSON
for i in 0 ..< Int((struct_name?.count)!) {
print((struct_name?[i].IJ!)!)
print((struct_name?[i].KL!)!)
}
break
case .failure(let error):
print("Error: \(error)")
break
}
}
qwerty
uiop
1234
asdf
let data = JSONValue(JSON!)
,然后就可以像这样提取值data["Id"]
。SwiftyJSON文档提供了如何以所需类型检索这些值的示例。你具体遇到了什么错误? - Isuru