我是Java Sounds的新手，我想循环播放2个不同的频率，每次播放1秒钟，在特定时间内。
例如，如果我有2个频率440hz和16000hz，时间为10秒，则每个“偶数”秒播放440hz，而每个“奇数”秒播放16000hz，即交替5秒钟。
我通过一些示例学习了一些东西，并且还编写了一个程序，借助这些示例，该程序可以在用户指定的时间内以单一频率运行。
如果有人能够帮助我解决这个问题，我将不胜感激。 谢谢。
我也附上了单一频率代码以供参考。
import java.nio.ByteBuffer;
import java.util.Scanner;
import javax.sound.sampled.*;
public class Audio {
public static void main(String[] args) throws InterruptedException, LineUnavailableException {
final int SAMPLING_RATE = 44100; // Audio sampling rate
final int SAMPLE_SIZE = 2; // Audio sample size in bytes
Scanner in = new Scanner(System.in);
int time = in.nextInt(); //Time specified by user in seconds
SourceDataLine line;
double fFreq = in.nextInt(); // Frequency of sine wave in hz
//Position through the sine wave as a percentage (i.e. 0 to 1 is 0 to 2*PI)
double fCyclePosition = 0;
//Open up audio output, using 44100hz sampling rate, 16 bit samples, mono, and big
// endian byte ordering
AudioFormat format = new AudioFormat(SAMPLING_RATE, 16, 1, true, true);
DataLine.Info info = new DataLine.Info(SourceDataLine.class, format);
if (!AudioSystem.isLineSupported(info)) {
System.out.println("Line matching " + info + " is not supported.");
throw new LineUnavailableException();
}
line = (SourceDataLine) AudioSystem.getLine(info);
line.open(format);
line.start();
// Make our buffer size match audio system's buffer
ByteBuffer cBuf = ByteBuffer.allocate(line.getBufferSize());
int ctSamplesTotal = SAMPLING_RATE * time; // Output for roughly user specified time in seconds
//On each pass main loop fills the available free space in the audio buffer
//Main loop creates audio samples for sine wave, runs until we tell the thread to exit
//Each sample is spaced 1/SAMPLING_RATE apart in time
while (ctSamplesTotal > 0) {
double fCycleInc = fFreq / SAMPLING_RATE; // Fraction of cycle between samples
cBuf.clear(); // Discard samples from previous pass
// Figure out how many samples we can add
int ctSamplesThisPass = line.available() / SAMPLE_SIZE;
for (int i = 0; i < ctSamplesThisPass; i++) {
cBuf.putShort((short) (Short.MAX_VALUE * Math.sin(2 * Math.PI * fCyclePosition)));
fCyclePosition += fCycleInc;
if (fCyclePosition > 1) {
fCyclePosition -= 1;
}
}
//Write sine samples to the line buffer. If the audio buffer is full, this will
// block until there is room (we never write more samples than buffer will hold)
line.write(cBuf.array(), 0, cBuf.position());
ctSamplesTotal -= ctSamplesThisPass; // Update total number of samples written
//Wait until the buffer is at least half empty before we add more
while (line.getBufferSize() / 2 < line.available()) {
Thread.sleep(1);
}
}
//Done playing the whole waveform, now wait until the queued samples finish
//playing, then clean up and exit
line.drain();
line.close();
}
}