我有一个自定义了recyclerView
的适配器,我想在recyclerView
的项上长按事件时打开一个弹出菜单。
我该怎么做?
我有一个自定义了recyclerView
的适配器,我想在recyclerView
的项上长按事件时打开一个弹出菜单。
我该怎么做?
这个问题已经在这里得到了解答。不管怎样,你可以像下面这样做:
class ViewHolder extends RecyclerView.ViewHolder implements View.OnClickListener, View.OnLongClickListener {
private Article article;
private TextView nameTextView;
public ViewHolder(View itemView) {
super(itemView);
itemView.setOnClickListener(this);
itemView.setOnLongClickListener(this);
nameTextView = (TextView) itemView.findViewById(R.id.grid_item_article_name_textView);
}
public void bind(Article article) {
this.article = article;
nameTextView.setText(article.getName());
}
@Override
public void onClick(View view) {
// Context context = view.getContext();
// article.getName()
}
@Override
public boolean onLongClick(View view) {
// Handle long click
// Return true to indicate the click was handled
return true;
}
}
更新:如果你正在使用Kotlin,请执行以下操作:
inner class ViewHolder(itemView: View) : RecyclerView.ViewHolder(itemView),
View.OnClickListener, View.OnLongClickListener {
init {
itemView.setOnClickListener(this)
itemView.setOnLongClickListener(this)
}
private lateinit var article: Article
private val titleTextView: TextView = itemView.findViewById(R.id.item_article_title_textView)
fun bind(article: Article) {
this.article = article
titleTextView.text = article.title
}
override fun onClick(view: View) {
listener.onItemClick(article)
}
override fun onLongClick(view: View): Boolean {
Toast.makeText(view.context, "long click", Toast.LENGTH_SHORT).show()
// Return true to indicate the click was handled
return true
}
}
我是这样做的:
static class ViewHolder extends RecyclerView.ViewHolder {
TextView tvName;
ViewHolder(View v) {
super(v);
tvName = (TextView) v.findViewById(R.id.textView_Username);
//Single Tapup
v.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
Toast.makeText(v.getContext(), "Position is " + getAdapterPosition(), Toast.LENGTH_SHORT).show();
}
});
//Long Press
v.setOnLongClickListener(new View.OnLongClickListener() {
@Override
public boolean onLongClick(View v) {
Toast.makeText(v.getContext(), "Position is " + getAdapterPosition(), Toast.LENGTH_SHORT).show();
return false;
}
});
}
}
首先,您需要注册您的Activity来监听来自recyclerView
的长按事件(这样就不必使用任何类型的onLongClickListener
):
registerForContextMenu(recyclerView);
然后,您需要创建一个菜单资源(context_menu.xml):
<?xml version="1.0" encoding="utf-8"?>
<menu xmlns:android="http://schemas.android.com/apk/res/android">
<item android:title="Mostra documento" android:id="@+id/context_menu_documents_fragment_view"></item>
<item android:title="Aggiungi ad un contenitore" android:id="@+id/context_menu_documents_fragment_add_to_box"></item>
<item android:title="Elimina documento" android:id="@+id/context_menu_documents_fragment_delete"></item>
</menu>
在注册上下文菜单的活动中,您需要重写以下方法:
@Override
public void onCreateContextMenu(ContextMenu menu, View v, ContextMenu.ContextMenuInfo menuInfo) {
super.onCreateContextMenu(menu, v, menuInfo);
// Inflate Menu from xml resource
MenuInflater menuInflater = getActivity().getMenuInflater();
menuInflater.inflate(R.menu.context_menu_documents_fragment, menu);
}
@Override
public boolean onContextItemSelected(MenuItem item) {
Toast.makeText(getActivity(), " User selected something ", Toast.LENGTH_LONG).show();
return false;
}
这非常重要,您需要修改 RecyclerView
适配器的代码,像这样:
@Override
public void onBindViewHolder(final DocumentViewHolder viewHolder, int position) {
...
viewHolder.itemView.setLongClickable(true);
...
}
现在您可以显示上下文菜单并拦截用户选择! 但是您无法知道用户单击了哪个项目,要做到这一点,您必须使用自定义RecyclerView,如下所示(Renaud Cerrato的原始代码):
public class ContextMenuRecyclerView extends RecyclerView {
private RecyclerContextMenuInfo mContextMenuInfo;
public ContextMenuRecyclerView(Context context) {
super(context);
}
public ContextMenuRecyclerView(Context context, AttributeSet attrs) {
super(context, attrs);
}
public ContextMenuRecyclerView(Context context, AttributeSet attrs, int defStyle) {
super(context, attrs, defStyle);
}
@Override
protected ContextMenu.ContextMenuInfo getContextMenuInfo() {
return mContextMenuInfo;
}
@Override
public boolean showContextMenuForChild(View originalView) {
final int longPressPosition = getChildAdapterPosition(originalView);
if (longPressPosition >= 0) {
final long longPressId = getAdapter().getItemId(longPressPosition);
mContextMenuInfo = new RecyclerContextMenuInfo(longPressPosition, longPressId);
return super.showContextMenuForChild(originalView);
}
return false;
}
public static class RecyclerContextMenuInfo implements ContextMenu.ContextMenuInfo {
public RecyclerContextMenuInfo(int position, long id) {
this.position = position;
this.id = id;
}
final public int position;
final public long id;
}
}
在之前的onContextItemSelected()
方法中,您可以使用此代码了解recyclerView
项的ID和位置:
ContextMenuRecyclerView.RecyclerContextMenuInfo info = (ContextMenuRecyclerView.RecyclerContextMenuInfo) item.getMenuInfo();
最后,您需要修改recyclerView适配器中的getItemId()方法和布局文件,以确保您使用自己的recyclerView而不是android的!
我曾经苦苦挣扎于在点击后获取项目位置,以下是我的解决方案:
public void onClick(View view) {
ViewHolder holder =(ViewHolder)view.getTag();
int position = holder.getLayoutPosition();
Log.d("testing ","pos" +position);
}