我一直在尝试在Keras中设置一个非线性回归问题。不幸的是,结果显示出过拟合。下面是代码:
model = Sequential()
model.add(Dense(number_of_neurons, input_dim=X_train.shape[1], activation='relu', kernel_regularizer=regularizers.l2(0)))
model.add(Dense(int(number_of_neurons), activation = 'relu', kernel_regularizer=regularizers.l2(0)))
model.add(Dense(int(number_of_neurons), activation='relu', kernel_regularizer=regularizers.l2(0)))
model.add(Dense(int(number_of_neurons), activation='relu',kernel_regularizer=regularizers.l2(0)))
model.add(Dense(int(number_of_neurons), activation='relu',kernel_regularizer=regularizers.l2(0)))
model.add(Dense(outdim, activation='linear'))
Adam = optimizers.Adam(lr=0.001)
model.compile(loss='mean_squared_error', optimizer=Adam, metrics=['mae'])
model.fit(X, Y, epochs=1000, batch_size=500, validation_split=0.2, shuffle=True, verbose=2 , initial_epoch=0)
没有正则化的结果显示在这里:Without regularization。训练的平均绝对误差要比验证小得多,并且两者之间有一个固定的差距,这是过拟合的迹象。
每个层都指定了L2正则化,如下所示,
model = Sequential()
model.add(Dense(number_of_neurons, input_dim=X_train.shape[1], activation='relu', kernel_regularizer=regularizers.l2(0.001)))
model.add(Dense(int(number_of_neurons), activation = 'relu', kernel_regularizer=regularizers.l2(0.001)))
model.add(Dense(int(number_of_neurons), activation='relu', kernel_regularizer=regularizers.l2(0.001)))
model.add(Dense(int(number_of_neurons), activation='relu',kernel_regularizer=regularizers.l2(0.001)))
model.add(Dense(int(number_of_neurons), activation='relu',kernel_regularizer=regularizers.l2(0.001)))
model.add(Dense(outdim, activation='linear'))
Adam = optimizers.Adam(lr=0.001)
model.compile(loss='mean_squared_error', optimizer=Adam, metrics=['mae'])
model.fit(X, Y, epochs=1000, batch_size=500, validation_split=0.2, shuffle=True, verbose=2 , initial_epoch=0)
这些结果显示在这里 L2正则化结果。测试的MAE接近于训练,这很好。然而,训练的MAE很差,为0.03(没有正则化时,它要低得多,为0.0028)。
我该怎么做才能通过正则化减少训练的MAE?