我有一段以毫秒为单位的时间,我想将它转换成“HH:MM:SS”格式。它应该会环绕,例如当
milliseconds = 86400000
时,我希望得到00:00:00
。milliseconds = 86400000
时,我希望得到00:00:00
。那么创建一个类似这样的函数怎么样:
function msToTime(duration) {
var milliseconds = Math.floor((duration % 1000) / 100),
seconds = Math.floor((duration / 1000) % 60),
minutes = Math.floor((duration / (1000 * 60)) % 60),
hours = Math.floor((duration / (1000 * 60 * 60)) % 24);
hours = (hours < 10) ? "0" + hours : hours;
minutes = (minutes < 10) ? "0" + minutes : minutes;
seconds = (seconds < 10) ? "0" + seconds : seconds;
return hours + ":" + minutes + ":" + seconds + "." + milliseconds;
}
console.log(msToTime(300000))
将毫秒时间转换为易读的时间格式。
function msToTime(ms) {
let seconds = (ms / 1000).toFixed(1);
let minutes = (ms / (1000 * 60)).toFixed(1);
let hours = (ms / (1000 * 60 * 60)).toFixed(1);
let days = (ms / (1000 * 60 * 60 * 24)).toFixed(1);
if (seconds < 60) return seconds + " Sec";
else if (minutes < 60) return minutes + " Min";
else if (hours < 24) return hours + " Hrs";
else return days + " Days"
}
console.log(msToTime(1000))
console.log(msToTime(10000))
console.log(msToTime(300000))
console.log(msToTime(3600000))
console.log(msToTime(86400000))
我有同样的问题,这是我最终做出的解决方案:
function parseMillisecondsIntoReadableTime(milliseconds){
//Get hours from milliseconds
var hours = milliseconds / (1000*60*60);
var absoluteHours = Math.floor(hours);
var h = absoluteHours > 9 ? absoluteHours : '0' + absoluteHours;
//Get remainder from hours and convert to minutes
var minutes = (hours - absoluteHours) * 60;
var absoluteMinutes = Math.floor(minutes);
var m = absoluteMinutes > 9 ? absoluteMinutes : '0' + absoluteMinutes;
//Get remainder from minutes and convert to seconds
var seconds = (minutes - absoluteMinutes) * 60;
var absoluteSeconds = Math.floor(seconds);
var s = absoluteSeconds > 9 ? absoluteSeconds : '0' + absoluteSeconds;
return h + ':' + m + ':' + s;
}
var time = parseMillisecondsIntoReadableTime(86400000);
alert(time);
这是我的解决方案
let h,m,s;
h = Math.floor(timeInMiliseconds/1000/60/60);
m = Math.floor((timeInMiliseconds/1000/60/60 - h)*60);
s = Math.floor(((timeInMiliseconds/1000/60/60 - h)*60 - m)*60);
// 获取时间格式 00:00:00
s < 10 ? s = `0${s}`: s = `${s}`
m < 10 ? m = `0${m}`: m = `${m}`
h < 10 ? h = `0${h}`: h = `${h}`
console.log(`${s}:${m}:${h}`);
s = \
${s < 10 ? '0': ''}${s}` `。这行代码的作用是将数字s转换为两位数的字符串形式,并在其前面添加'0'以实现对齐。 - seniorpreacher这个函数返回类似于YouTube视频的时间
function getYoutubeLikeToDisplay(millisec) {
var seconds = (millisec / 1000).toFixed(0);
var minutes = Math.floor(seconds / 60);
var hours = "";
if (minutes > 59) {
hours = Math.floor(minutes / 60);
hours = (hours >= 10) ? hours : "0" + hours;
minutes = minutes - (hours * 60);
minutes = (minutes >= 10) ? minutes : "0" + minutes;
}
seconds = Math.floor(seconds % 60);
seconds = (seconds >= 10) ? seconds : "0" + seconds;
if (hours != "") {
return hours + ":" + minutes + ":" + seconds;
}
return minutes + ":" + seconds;
}
输出:
抱歉,来晚了。被接受的答案对我没用,所以我自己写了一个。
2h 59s
1h 59m
1h
1h 59s
59m 59s
59s
代码(TypeScript):
function timeConversion(duration: number) {
const portions: string[] = [];
const msInHour = 1000 * 60 * 60;
const hours = Math.trunc(duration / msInHour);
if (hours > 0) {
portions.push(hours + 'h');
duration = duration - (hours * msInHour);
}
const msInMinute = 1000 * 60;
const minutes = Math.trunc(duration / msInMinute);
if (minutes > 0) {
portions.push(minutes + 'm');
duration = duration - (minutes * msInMinute);
}
const seconds = Math.trunc(duration / 1000);
if (seconds > 0) {
portions.push(seconds + 's');
}
return portions.join(' ');
}
console.log(timeConversion((60 * 60 * 1000) + (59 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion((60 * 60 * 1000) + (59 * 60 * 1000) ));
console.log(timeConversion((60 * 60 * 1000) ));
console.log(timeConversion((60 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion( (59 * 60 * 1000) + (59 * 1000)));
console.log(timeConversion( (59 * 1000)));
function convertMS(ms) {
var d, h, m, s;
s = Math.floor(ms / 1000);
m = Math.floor(s / 60);
s = s % 60;
h = Math.floor(m / 60);
m = m % 60;
d = Math.floor(h / 24);
h = h % 24;
h += d * 24;
return h + ':' + m + ':' + s;
}
return (h < 10 ? "0" + h : h) + ":" + (m < 10 ? "0" + m : m) + ":" + (s < 10 ? "0" + s : s);
,因为用数学计算比字符串操作更好。 - Mitch McMabershh:mm:ss
(1:59:59
或01:59:59
)
(1:59
或01:59
)
(默认:不填充)
基于 Chand 的回答稍作修改。
function formatMilliseconds(milliseconds, padStart) {
function pad(num) {
return `${num}`.padStart(2, '0');
}
let asSeconds = milliseconds / 1000;
let hours = undefined;
let minutes = Math.floor(asSeconds / 60);
let seconds = Math.floor(asSeconds % 60);
if (minutes > 59) {
hours = Math.floor(minutes / 60);
minutes %= 60;
}
return hours
? `${padStart ? pad(hours) : hours}:${pad(minutes)}:${pad(seconds)}`
: `${padStart ? pad(minutes) : minutes}:${pad(seconds)}`;
}
测试:
let s = 1000;
let m = 60*s;
let h = 60*m;
console.log(formatMilliseconds(1*h)); // 1:00:00
console.log(formatMilliseconds(1*h, true)); // 01:00:00
console.log(formatMilliseconds(59*m + 59*s)); // 59:59
console.log(formatMilliseconds(59*m + 59*s, true)); // 59:59
console.log(formatMilliseconds(9*m + 9*s)); // 9:09
console.log(formatMilliseconds(9*m + 9*s, true)); // 09:09
console.log(formatMilliseconds(5*s)); // 0:05
console.log(formatMilliseconds(5*s, true)); // 00:05
console.log(formatMilliseconds(2400*s)); // 40:00
console.log(formatMilliseconds(2400*s, true)); // 40:00
(asSeconds % 1).toFixed(3).substring(1)
`${padStart ? pad(hours) : hours}:${pad(minutes)}:${pad(seconds)}${(asSeconds % 1).toFixed(3).substring(1)}`
可能有更好的方法来实现这个目标,但这种朴素的解决方案能够完成工作。
测试:
let asSeconds = 59.5219;
let seconds = Math.floor(asSeconds);
console.log(`${pad(seconds)}${(asSeconds % 1).toFixed(3).substring(1)}`);
// Equivalent to above, without using `pad()`:
//console.log(`${String(seconds).padStart(2, '0')}${(asSeconds % 1).toFixed(3).substring(1)}`);
// Output: 59.522
我只需要一天的时间,24小时,这是我的想法:
const milliseconds = 5680000;
const hours = `0${new Date(milliseconds).getHours() - 1}`.slice(-2);
const minutes = `0${new Date(milliseconds).getMinutes()}`.slice(-2);
const seconds = `0${new Date(milliseconds).getSeconds()}`.slice(-2);
const time = `${hours}:${minutes}:${seconds}`
console.log(time);
function parseDuration(duration) {
let remain = duration
let days = Math.floor(remain / (1000 * 60 * 60 * 24))
remain = remain % (1000 * 60 * 60 * 24)
let hours = Math.floor(remain / (1000 * 60 * 60))
remain = remain % (1000 * 60 * 60)
let minutes = Math.floor(remain / (1000 * 60))
remain = remain % (1000 * 60)
let seconds = Math.floor(remain / (1000))
remain = remain % (1000)
let milliseconds = remain
return {
days,
hours,
minutes,
seconds,
milliseconds
};
}
function formatTime(o, useMilli = false) {
let parts = []
if (o.days) {
let ret = o.days + ' day'
if (o.days !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.hours) {
let ret = o.hours + ' hour'
if (o.hours !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.minutes) {
let ret = o.minutes + ' minute'
if (o.minutes !== 1) {
ret += 's'
}
parts.push(ret)
}
if (o.seconds) {
let ret = o.seconds + ' second'
if (o.seconds !== 1) {
ret += 's'
}
parts.push(ret)
}
if (useMilli && o.milliseconds) {
let ret = o.milliseconds + ' millisecond'
if (o.milliseconds !== 1) {
ret += 's'
}
parts.push(ret)
}
if (parts.length === 0) {
return 'instantly'
} else {
return parts.join(' ')
}
}
function formatTimeHMS(o) {
let hours = o.hours.toString()
if (hours.length === 1) hours = '0' + hours
let minutes = o.minutes.toString()
if (minutes.length === 1) minutes = '0' + minutes
let seconds = o.seconds.toString()
if (seconds.length === 1) seconds = '0' + seconds
return hours + ":" + minutes + ":" + seconds
}
function formatDurationHMS(duration) {
let time = parseDuration(duration)
return formatTimeHMS(time)
}
function formatDuration(duration, useMilli = false) {
let time = parseDuration(duration)
return formatTime(time, useMilli)
}
console.log(formatDurationHMS(57742343234))
console.log(formatDuration(57742343234))
console.log(formatDuration(5423401000))
console.log(formatDuration(500))
console.log(formatDuration(500, true))
console.log(formatDuration(1000 * 30))
console.log(formatDuration(1000 * 60 * 30))
console.log(formatDuration(1000 * 60 * 60 * 12))
console.log(formatDuration(1000 * 60 * 60 * 1))
var milliseconds = Math.floor(duration % 1000);
这样写。 - pseudozach