如何使用jq从JSON数组/对象中获取多个值

Question

如何使用jq在单行中从JSON数组/对象中获取多个值？

以下是curl请求和其响应：

curl -s -k --location --request GET "https://${HOSTNAME}/api/v1/projects/myProjects?page=1&pageSize=2" --header "Authorization: Bearer "$token"" | jq -r '.["data"]'


# Response
[
  {
    "id": "8a70803f8045722601804f62d54c5d9d",
    "createdBy": "8a70802980325cdc0180326b5fe60006",
    "createdDate": "2022-04-22T03:48:38.860+0000",
    "modifiedBy": "8a70802980325cdc0180326b5fe60006",
    "modifiedDate": "2022-04-22T03:48:38.860+0000",
    "version": null,
    "inactive": false,
    "name": "Netbank734113",
  },
  {
    "id": "8a70801c804568ae01804f625a923f8d",
    "createdBy": "8a70802980325cdc0180326b5fe60006",
    "createdDate": "2022-04-22T03:48:07.442+0000",
    "modifiedBy": "8a70802980325cdc0180326b5fe60006",
    "modifiedDate": "2022-04-22T03:48:07.442+0000",
    "version": null,
    "inactive": false,
    "name": "Netbank734112",
  }
]

现在尝试以下命令以在一行中获取id和name，但会出现重复结果。

result=$(curl -s -k --location --request GET "https://${HOSTNAME}/api/v1/projects/myProjects?page=1&pageSize=2" --header "Authorization: Bearer "$token"" | jq -r '.["data"]|.[].name +" "+  .[].id')

echo "$result"

# response
Netbank734113 8a70803f8045722601804f62d54c5d9d
Netbank734112 8a70803f8045722601804f62d54c5d9d
Netbank734113 8a70801c804568ae01804f625a923f8d
Netbank734112 8a70801c804568ae01804f625a923f8d

如何去除重复值并获得以下响应？

Netbank734113 8a70803f8045722601804f62d54c5d9d
Netbank734112 8a70801c804568ae01804f625a923f8d

使用您提供的输入尝试此命令，得到以下错误，请问如何修改该curl命令以获得预期结果。

result=$(curl -s -k --location --request GET "https://${HOSTNAME}/api/v1/projects/myProjects?page=1&pageSize=2" --header "Authorization: Bearer "$token"" | jq -r '["data"]|.[].unique_by(.name, .id) | map([.name, .id])[] | @tsv')

# error response

jq: error: syntax error, unexpected '(', expecting $end (Unix shell quoting issues?) at <top-level>, line 1:
["data"]|.[].unique_by(.name, .id) | map([.name, .id])[] | @tsv                      
jq: 1 compile error
 
# This one worked
result=$(curl -s -k --location --request GET "https://${HOSTNAME}/api/v1/projects/myProjects?page=1&pageSize=2" --header "Authorization: Bearer "$token"" | jq -r '.["data"]|.[]|.| .name + " " + .id')

- devops-admin

Answer 1

使用 .[].name + " " + .[].id' 的方法会迭代两次数组。改为一次迭代并同时提取你的数据：

curl … | jq -r '.data[] | .name + " " + .id'

Netbank734113 8a70803f8045722601804f62d54c5d9d
Netbank734112 8a70801c804568ae01804f625a923f8d

演示

---

您可能还对使用字符串插值感兴趣：

curl … | jq -r '.data[] | "\(.name) \(.id)"'

演示

- pmf

---

如果两个都是字符串，.name + " " + .id 就能够工作，但如果 id 是一个数字就不能工作。 - Alexx Roche

@AlexxRoche (.id | tostring) 或者 (.id | @text)，或者使用字符串插值来将其转换为字符串，如果需要的话。 - pmf