我有一个foreach
循环,并需要在List
中选择最后一项时执行一些逻辑,例如:
foreach (Item result in Model.Results)
{
//if current result is the last item in Model.Results
//then do something in the code
}
我可以在不使用for循环和计数器的情况下知道哪个循环是最后一个吗?
我有一个foreach
循环,并需要在List
中选择最后一项时执行一些逻辑,例如:
foreach (Item result in Model.Results)
{
//if current result is the last item in Model.Results
//then do something in the code
}
我可以在不使用for循环和计数器的情况下知道哪个循环是最后一个吗?
List<int> ListInt = new List<int> { 1, 2, 3, 4, 5, 6, 7, 8, 9, 10 };
int count = ListInt.Count;
int index = 1;
foreach (var item in ListInt)
{
if (index != count)
{
Console.WriteLine("do something at index number " + index);
}
else
{
Console.WriteLine("Foreach loop, this is the last iteration of the loop " + index);
}
index++;
}
//OR
int count = ListInt.Count;
int index = 1;
foreach (var item in ListInt)
{
if (index < count)
{
Console.WriteLine("do something at index number " + index);
}
else
{
Console.WriteLine("Foreach loop, this is the last iteration of the loop " + index);
}
index++;
}
如果要对除最后一个元素以外的每个元素执行额外操作,则可以使用基于函数的方法。
delegate void DInner ();
....
Dinner inner=delegate
{
inner=delegate
{
// do something additional
}
}
foreach (DataGridViewRow dgr in product_list.Rows)
{
inner()
//do something
}
}
foreach (DataGridViewRow dgr in product_list.Rows)
{
if (dgr.Index == dgr.DataGridView.RowCount - 1)
{
//do something
}
}
foreach (DataRow drow in ds.Tables[0].Rows)
{
cnt_sl1 = "<div class='col-md-6'><div class='Slider-img'>" +
"<div class='row'><img src='" + drow["images_path"].ToString() + "' alt='' />" +
"</div></div></div>";
cnt_sl2 = "<div class='col-md-6'><div class='Slider-details'>" +
"<p>" + drow["situation_details"].ToString() + "</p>" +
"</div></div>";
if (i == 0)
{
lblSituationName.Text = drow["situation"].ToString();
}
if (drow["images_position"].ToString() == "0")
{
content += "<div class='item'>" + cnt_sl1 + cnt_sl2 + "</div>";
cnt_sl1 = "";
cnt_sl2 = "";
}
else if (drow["images_position"].ToString() == "1")
{
content += "<div class='item'>" + cnt_sl2 + cnt_sl1 + "</div>";
cnt_sl1 = "";
cnt_sl2 = "";
}
i++;
}