你的代码可能不会像你想的那样运行。异步方法在开始等待异步结果后立即返回。使用跟踪功能来调查代码实际运行情况是很有见地的。
以下代码执行以下操作:
- 创建4个任务
- 每个任务都会异步递增一个数字并返回递增后的数字
- 当异步结果到达时,它会被跟踪。
static TypeHashes _type = new TypeHashes(typeof(Program));
private void Run()
{
TracerConfig.Reset("debugoutput");
using (Tracer t = new Tracer(_type, "Run"))
{
for (int i = 0; i < 4; i++)
{
DoSomeThingAsync(i);
}
}
Application.Run();
}
private async void DoSomeThingAsync(int i)
{
using (Tracer t = new Tracer(_type, "DoSomeThingAsync"))
{
t.Info("Hi in DoSomething {0}",i);
try
{
int result = await Calculate(i);
t.Info("Got async result: {0}", result);
}
catch (ArgumentException ex)
{
t.Error("Got argument exception: {0}", ex);
}
}
}
Task<int> Calculate(int i)
{
var t = new Task<int>(() =>
{
using (Tracer t2 = new Tracer(_type, "Calculate"))
{
if( i % 2 == 0 )
throw new ArgumentException(String.Format("Even argument {0}", i));
return i++;
}
});
t.Start();
return t;
}
当您观察跟踪时
22:25:12.649 02172/02820 { AsyncTest.Program.Run
22:25:12.656 02172/02820 { AsyncTest.Program.DoSomeThingAsync
22:25:12.657 02172/02820 Information AsyncTest.Program.DoSomeThingAsync Hi in DoSomething 0
22:25:12.658 02172/05220 { AsyncTest.Program.Calculate
22:25:12.659 02172/02820 { AsyncTest.Program.DoSomeThingAsync
22:25:12.659 02172/02820 Information AsyncTest.Program.DoSomeThingAsync Hi in DoSomething 1
22:25:12.660 02172/02756 { AsyncTest.Program.Calculate
22:25:12.662 02172/02820 { AsyncTest.Program.DoSomeThingAsync
22:25:12.662 02172/02820 Information AsyncTest.Program.DoSomeThingAsync Hi in DoSomething 2
22:25:12.662 02172/02820 { AsyncTest.Program.DoSomeThingAsync
22:25:12.662 02172/02820 Information AsyncTest.Program.DoSomeThingAsync Hi in DoSomething 3
22:25:12.664 02172/02756 } AsyncTest.Program.Calculate Duration 4ms
22:25:12.666 02172/02820 } AsyncTest.Program.Run Duration 17ms ---- Run has completed. The async methods are now scheduled on different threads.
22:25:12.667 02172/02756 Information AsyncTest.Program.DoSomeThingAsync Got async result: 1
22:25:12.667 02172/02756 } AsyncTest.Program.DoSomeThingAsync Duration 8ms
22:25:12.667 02172/02756 { AsyncTest.Program.Calculate
22:25:12.665 02172/05220 Exception AsyncTest.Program.Calculate Exception thrown: System.ArgumentException: Even argument 0
at AsyncTest.Program.c__DisplayClassf.Calculateb__e() in C:\Source\AsyncTest\AsyncTest\Program.cs:line 124
at System.Threading.Tasks.Task`1.InvokeFuture(Object futureAsObj)
at System.Threading.Tasks.Task.InnerInvoke()
at System.Threading.Tasks.Task.Execute()
22:25:12.668 02172/02756 Exception AsyncTest.Program.Calculate Exception thrown: System.ArgumentException: Even argument 2
at AsyncTest.Program.c__DisplayClassf.Calculateb__e() in C:\Source\AsyncTest\AsyncTest\Program.cs:line 124
at System.Threading.Tasks.Task`1.InvokeFuture(Object futureAsObj)
at System.Threading.Tasks.Task.InnerInvoke()
at System.Threading.Tasks.Task.Execute()
22:25:12.724 02172/05220 } AsyncTest.Program.Calculate Duration 66ms
22:25:12.724 02172/02756 } AsyncTest.Program.Calculate Duration 57ms
22:25:12.725 02172/05220 Error AsyncTest.Program.DoSomeThingAsync Got argument exception: System.ArgumentException: Even argument 0
Server stack trace:
at AsyncTest.Program.c__DisplayClassf.Calculateb__e() in C:\Source\AsyncTest\AsyncTest\Program.cs:line 124
at System.Threading.Tasks.Task`1.InvokeFuture(Object futureAsObj)
at System.Threading.Tasks.Task.InnerInvoke()
at System.Threading.Tasks.Task.Execute()
Exception rethrown at [0]:
at System.Runtime.CompilerServices.TaskAwaiter.EndAwait()
at System.Runtime.CompilerServices.TaskAwaiter`1.EndAwait()
at AsyncTest.Program.DoSomeThingAsyncd__8.MoveNext() in C:\Source\AsyncTest\AsyncTest\Program.cs:line 106
22:25:12.725 02172/02756 Error AsyncTest.Program.DoSomeThingAsync Got argument exception: System.ArgumentException: Even argument 2
Server stack trace:
at AsyncTest.Program.c__DisplayClassf.Calculateb__e() in C:\Source\AsyncTest\AsyncTest\Program.cs:line 124
at System.Threading.Tasks.Task`1.InvokeFuture(Object futureAsObj)
at System.Threading.Tasks.Task.InnerInvoke()
at System.Threading.Tasks.Task.Execute()
Exception rethrown at [0]:
at System.Runtime.CompilerServices.TaskAwaiter.EndAwait()
at System.Runtime.CompilerServices.TaskAwaiter`1.EndAwait()
at AsyncTest.Program.DoSomeThingAsyncd__8.MoveNext() in C:\Source\AsyncTest\AsyncTest\Program.cs:line 0
22:25:12.726 02172/05220 } AsyncTest.Program.DoSomeThingAsync Duration 70ms
22:25:12.726 02172/02756 } AsyncTest.Program.DoSomeThingAsync Duration 64ms
22:25:12.726 02172/05220 { AsyncTest.Program.Calculate
22:25:12.726 02172/05220 } AsyncTest.Program.Calculate Duration 0ms
22:25:12.726 02172/05220 Information AsyncTest.Program.DoSomeThingAsync Got async result: 3
22:25:12.726 02172/05220 } AsyncTest.Program.DoSomeThingAsync Duration 64ms
您会注意到,当只有一个子线程完成(2756)时,Run方法在2820线程上完成。如果在await方法周围放置try/catch,您可以以通常的方式“捕获”异常,尽管在计算任务完成并执行您的contination时,您的代码在另一个线程上执行。
由于我使用了
ApiChange工具中的ApiChange.Api.dll,因此计算方法会自动跟踪抛出的异常。跟踪和反编译有助于理解发生了什么。为了摆脱线程,您可以创建自己的GetAwaiter BeginAwait和EndAwait版本,并包装不是任务而是例如Lazy,在自己的扩展方法内部进行跟踪。然后,您将更好地了解编译器和TPL的操作。
现在,您会发现没有办法将异常返回到try/catch中,因为没有堆栈帧可用于传播任何异常。在启动异步操作后,您的代码可能正在执行完全不同的操作。它可能调用Thread.Sleep甚至终止。只要还有一个前台线程,您的应用程序就会愉快地继续执行异步任务。
在异步操作完成并回调到UI线程后,您可以在异步方法内处理异常。建议的做法是使用TaskScheduler.FromSynchronizationContext。这仅适用于具有UI线程且未忙于其他事情的情况。