我想从用户表单将一个SQL参数传递给我的报告类,但它无法工作,不会创建报告,当我在将ID参数添加到报告类后再次打开报告设计器选项卡时,它会刷新报告并删除我的组件。
问题出在哪里?
这是我的报告类:
public SodoorZemanatName(long ID)
{
InitializeComponent(ID);
}
protected override void Dispose(bool disposing)
{
if (disposing && (components != null))
{
components.Dispose();
}
base.Dispose(disposing);
}
#region Designer generated code
private void InitializeComponent(long ID)
{
this.components = new System.ComponentModel.Container();
DevExpress.DataAccess.Sql.CustomSqlQuery customSqlQuery1 = new DevExpress.DataAccess.Sql.CustomSqlQuery();
DevExpress.DataAccess.Sql.QueryParameter queryParameter1 = new DevExpress.DataAccess.Sql.QueryParameter();
System.ComponentModel.ComponentResourceManager resources = new System.ComponentModel.ComponentResourceManager(typeof(SodoorZemanatName));
this.topMarginBand1 = new DevExpress.XtraReports.UI.TopMarginBand();
this.detailBand1 = new DevExpress.XtraReports.UI.DetailBand();
this.bottomMarginBand1 = new DevExpress.XtraReports.UI.BottomMarginBand();
this.sqlDataSource2 = new DevExpress.DataAccess.Sql.SqlDataSource(this.components);
((System.ComponentModel.ISupportInitialize)(this)).BeginInit();
this.topMarginBand1.HeightF = 100F;
this.topMarginBand1.Name = "topMarginBand1";
this.detailBand1.HeightF = 100F;
this.detailBand1.Name = "detailBand1";
this.bottomMarginBand1.HeightF = 100F;
this.bottomMarginBand1.Name = "bottomMarginBand1";
this.sqlDataSource2.ConnectionName = "Context";
this.sqlDataSource2.Name = "sqlDataSource2";
customSqlQuery1.Name = "Query";
queryParameter1.Name = "ID";
queryParameter1.Type = typeof(long);
queryParameter1.ValueInfo = "0";
queryParameter1.Value = ID;
customSqlQuery1.Parameters.Add(queryParameter1);
customSqlQuery1.Sql = "select * from LG_Garanti where ID=@ID";
this.sqlDataSource2.Queries.AddRange(new DevExpress.DataAccess.Sql.SqlQuery[] {
customSqlQuery1});
this.sqlDataSource2.ResultSchemaSerializable = resources.GetString("sqlDataSource2.ResultSchemaSerializable");
this.Bands.AddRange(new DevExpress.XtraReports.UI.Band[] {
this.topMarginBand1,
this.detailBand1,
this.bottomMarginBand1});
this.ComponentStorage.AddRange(new System.ComponentModel.IComponent[] {
this.sqlDataSource2});
this.DataSource = this.sqlDataSource2;
this.Version = "15.2";
((System.ComponentModel.ISupportInitialize)(this)).EndInit();
}
#endregion
这是我的呼唤:
SodoorZemanatName report = new SodoorZemanatName(1);
ASPxDocumentViewer1.ReportTypeName = "SodoorZemanatName";
ASPxDocumentViewer1.Report = report;
new DevExpress.XtraReports.UI.XtraReport();
是不够的,因为它不知道如何使用你的数据源,如何展示数据。DevExpress.XtraReports.UI.XtraReport report = new your_report_design_class();
在过去,我曾经使用过这种方式,在分配数据源之前必须先创建一个带有我的设计的新报告。 - minhhn2910