访问继承成员

Question

我有一个继承自Loan的LoanWithClient模型：

public class LoanWithClient : Loan
{
    public Client Client { get; set; }
}

如何在不必显式编写其属性的情况下访问整个继承的Loan对象？

LoanWithClient不包含名为Loan的定义。

return new LoanWithClient
{
     **Loan** = loan, //The Loan is erroring: LoanWithClient does not contain a definition for Loan
     Client = client
};

贷款类：

public class Loan
{
    public int ID { get; set; }
    public string Address { get; set; }
    public string City { get; set; }
    //etc..
}

- user3378165

---

请定义名为 Loan 的类。 - Rahul

我认为你可能误解了“继承”的含义。它意味着派生类（LoanWithClient）继承其父类（Loan）的特征（方法、属性等）。如果既没有LoanWithClient也没有Loan属性Loan，那么在构造实例时就无法使用它。如果Loan有一个Amount属性，你可以像使用Client一样直接使用它。 - ProgrammingLlama

创建一个构造函数并从中调用基类构造函数。例如，请参见https://dev59.com/0HVD5IYBdhLWcg3wVKEb - DodgyCodeException

另外，你的对象模型看起来有点可疑。地址真的是贷款的属性吗？ - DodgyCodeException

也许你正在寻找装饰器模式？（另请参阅：装饰器模式维基百科页面） - ProgrammingLlama

不要混淆"is-a"和"has-a"。LoanWithClient是一个Loan，它并没有拥有一个Loan。 - Damien_The_Unbeliever

Answer 1

LoanWithClient类继承自Loan类，这意味着子类拥有父类的所有属性。但这并不意味着子类包含一个父类作为属性。您可以像这样编写类-

public class Loan
{
    public int ID { get; set; }
    public string Address { get; set; }
    public string City { get; set; }
    //etc..
}

public class LoanWithClient
{
    public Loan Loan { get; set; }
    public Client Client { get; set; }
}

return new LoanWithClient
{
     Loan = loan,
     Client = client
};

如果您想保留类架构，可以返回以下方式-

return new LoanWithClient
{
     ID = loan.ID,
     Address = loan.Address,
     City = loan.City,
     //etc..
     Client = client
};

- Ashique

Answer 2

您想要

访问继承的成员

Loan 不是成员，它是父级。 像这样访问 Loan 的成员：

return new LoanWithClient
{
     ID = loan.ID,
     Address = loan.Address,
     City = loan.City,
     //etc...
     Client = client
};

- shingo