我已经试图让这个函数工作了两个小时,但是找不到错误在哪里。
这个行为很出乎意料。
当表单中的任何一个字段被填写时,表单会被提交到php文件,并且只有在所有字段都为空时(即5个错误),才会显示错误。
但是当6个字段中的任何一个被填写时,表单会被提交,而不管表单中的其他错误。
请帮助我验证这个表单。
error
是我将向用户显示的错误信息。 errors
是发现的错误数量。
JavaScript函数
function formValidator(){
var elementValue = document.getElementById("first-name").value;
var elementName = document.getElementById("first-name");
var errors = 0;
var error = " ";
if (elementValue == "" || elementValue == " " || elementValue== NULL){
error = "First Name shouldn't be left empty.";
errors = 1;
}
var elementValue = document.getElementById("last-name").value;
var elementName = document.getElementById("last-name");
if (elementValue == "" || elementValue == " " || elementValue== NULL){
if (errors == 0){
error = "Last Name shouldn't be left empty.";
}
else{
error += "<br>Last Name shouldn't be left empty.";
}
errors+=1;
}
var elementValue = document.getElementById("email-for-registration").value;
var elementName = document.getElementById("email-for-registration");
var email_err = "false";
if (elementValue == "" || elementValue == " " || elementValue== NULL){
email_err = "true";
}
var elementValue = document.getElementById("phone-for-registration").value;
if ((elementValue == "" || elementValue == " " || elementValue== NULL) && email_err == "true"){
if (errors == 0){
error = "Both email and contact cannot be left empty.";
}
else{
error += "<br>Both email and contact cannot be left empty.";
}
errors+=1;
}
var elementValue = document.getElementById("password-for-registration").value;
var elementName = document.getElementById("password-for-registration");
if (elementValue == "" || elementValue == " " || elementValue== NULL){
if (errors == 0){
error = "Password shouldn't be left empty.\nSelect a strong password atleast 6 characters long.";
}
else{
error += "<br>Password shouldn't be left empty.Select a strong password atleast 6 characters long.";
}
errors+=1;
}
else if (elementValue.length<6){
if (errors == 0){
error = "Password less than 6 characters aren't allowed for security reasons.";
}
else{
error += "<br>Password less than 6 characters aren't allowed for security reasons.";
}
errors+=1;
}
email_err = document.getElementById("confirm-password-for-registration").value;
var elementName = document.getElementById("confirm-password-for-registration");
if (elementValue != email_err){
if (errors == 0){
error = "The password to confirm doesn't match with your desired password.";
}
else{
error += "<br>The password to confirm doesn't match with your desired password.";
}
errors+=1;
}
var elementValue = document.getElementById("agreed-for-registration");
var elementName = document.getElementById("agreed-for-registration");
if (!elementValue.checked){
if (errors == 0){
error = "Please go through our <a href=''>Terms and Conditions</a>, and make sure you agree to continue.";
document.getElementById("agreed-for-registration").focus();
}
else{
error += "<br>Please go through our <a href=''>Terms and Conditions</a>, and make sure you agree to continue.";
}
errors+=1;
}
alert(errors);
if (errors > 1){
document.getElementById("form_errors").innerHTML = "<h4 style='color:red;'>Please remove the following errors from form to continue.</h4>";
document.getElementById("form_errors").innerHTML += "<h5>" + error + "</h5><br>";
return false;
} else if (errors == 1){
alert(error);
elementName.focus();
return false;
} else if (errors == 0){
return true;
}
return false;
}
在这里调用了函数。
<form name="registration" class="deco_blu_form" action="<?=$base_url;?>forms/confirm-registration/members.php" method="post" onsubmit="return formValidator();">
如果需要其他信息、代码或解释,请提出。
NULL
而不是null
是否是问题所在。 - RobH