我该如何使用过程式编程方式计算以下两个日期之间的月数?
PHP代码。
PHP代码。
$delete_date = "2000-01-12 08:02:39";
$current_date = date('Y-m-d H:i:s'); //current date
$delete_date = "2000-01-12 08:02:39";
$current_date = date('Y-m-d H:i:s'); //current date
$delete_date = "2000-01-12 08:02:39";
$date_format = 'Y-m-d H:i:s';
$current_date = date($date_format);
$diff = date_diff(date_create_from_format($date_format, $delete_date), date_create());
$months = $diff->m;
Something along the lines of that.
使用DateTime可以这样获取总月数:
$d1 = new DateTime("2000-01-12 08:02:39");
$d2 = new DateTime();
$d3 = $d1->diff($d2);
$months = ($d3->y*12)+$d3->m;
你仍然需要处理剩余的天数 $d3->d
... 但这取决于你的需求。
$delete_date = "2000-01-12 08:02:39";
$current_date = date('Y-m-d H:i:s'); //current date
$diff = strtotime($current_date) - strtotime($delete_date);
$months = floor(floatval($diff) / (60 * 60 * 24 * 365 / 12));
echo $months . "\n";
floor
、round
或ceil
来四舍五入月份计数可以吗? - scoffey这是你在寻找的吗?
$delete_date = "2000-01-12 08:02:39";
$current_date = date('Y-m-d H:i:s'); //current date
// convert date to int
$delete_date = strtotime($delete_date);
$current_date = strtotime($current_date);
// calculate it
$diff = $delete_date - $current_date;
// convert int to time
$conv_diff = date('format', $diff);
试试这个,很容易,可能不够高级,但非常有效。
function calculateMonthsBetweenDates($fMonth, $fDay, $fYear, $tMonth, $tDay, $tYear)
{
//Build datetime vars using month, day and year
$dateFrom = mktime(0, 0, 0, $fMonth, $fDay, $fYear);
$dateTo = mktime(0, 0, 0, $tMonth, $tDay, $tYear);
//Check dateTo is a later date than dateFrom.
if($dateFrom<=$dateTo){
$yearF = date("Y", $dateFrom);
$yearT = date("Y", $dateTo);
$monthF = date("m", $dateFrom);
$monthT = date("m", $dateTo);
//same year
if ($yearF == $yearT)
$months = ($monthT - $monthF);
else{
//different year
$months = (12*($yearT-$yearF)-$monthF) + $monthT;
}
return $months;
}
else
return false; //or -1
}