使用内置函数next()
,可以逐步迭代生成器。例如:
def sync_gen(n):
"""Simple generator"""
for i in range(n):
yield i**2
sg = sync_gen(4)
print(next(sg)) # -> 0
print(next(sg)) # -> 1
print(next(sg)) # -> 4
在异步生成器上使用 next()
不起作用:
import asyncio
async def async_gen(n):
for i in range(n):
yield i**2
async def main():
print("Async for:")
async for v in async_gen(4): # works as expected
print(v)
print("Async next:")
ag = async_gen(4)
v = await next(ag) # raises: TypeError: 'async_generator' object is not an iterator
print(v)
asyncio.run(main())
是否存在类似v = await async_next(ag)
这样的方式来获得与普通生成器相同的行为?
await iterator.__anext__()
。 - Frank Yellin