MySQL的WEEK()
函数的哪种模式可以得到ISO 8601年的周数?WEEK()
函数的第二个参数按照此表设置模式:
+--------------------------------------------------------------------+
| Mode | First day of week | Range | Week 1 is the first week ... |
|------+-------------------+-------+---------------------------------|
| 0 | Sunday | 0-53 | with a Sunday in this year |
|------+-------------------+-------+---------------------------------|
| 1 | Monday | 0-53 | with more than 3 days this year |
|------+-------------------+-------+---------------------------------|
| 2 | Sunday | 1-53 | with a Sunday in this year |
|------+-------------------+-------+---------------------------------|
| 3 | Monday | 1-53 | with more than 3 days this year |
|------+-------------------+-------+---------------------------------|
| 4 | Sunday | 0-53 | with more than 3 days this year |
|------+-------------------+-------+---------------------------------|
| 5 | Monday | 0-53 | with a Monday in this year |
|------+-------------------+-------+---------------------------------|
| 6 | Sunday | 1-53 | with more than 3 days this year |
|------+-------------------+-------+---------------------------------|
| 7 | Monday | 1-53 | with a Monday in this year |
+--------------------------------------------------------------------+
这些模式中是否有一种可以给出 ISO 8601 年份的周数?