在 Swift 中是否可以循环枚举值?或者有什么替代方法吗?
我正在学习苹果的 Swift 语言指南,看到了这个关于枚举的示例。
// EXPERIMENT
//
// Add a method to Card that creates a full deck of cards,
// with one card of each combination of rank and suit.
struct Card {
var rank: Rank
var suit: Suit
func simpleDescription() -> String {
return "The \(rank.simpleDescription()) of \(suit.simpleDescription())"
}
}
let threeOfSpades = Card(rank: .Three, suit: .Spades)
let threeOfSpadesDescription = threeOfSpades.simpleDescription()
enum Suit {
case Spades, Hearts, Diamonds, Clubs
func simpleDescription() -> String {
switch self {
case .Spades:
return "spades"
case .Hearts:
return "hearts"
case .Diamonds:
return "diamonds"
case .Clubs:
return "clubs"
}
}
}
enum Rank: Int {
case Ace = 1
case Two, Three, Four, Five, Six, Seven, Eight, Nine, Ten
case Jack, Queen, King
func simpleDescription() -> String {
switch self {
case .Ace:
return "ace"
case .Jack:
return "jack"
case .Queen:
return "queen"
case .King:
return "king"
default:
return String(self.toRaw())
}
}
}
摘自:Apple Inc.《The Swift Programming Language》iBooks。https://itun.es/us/jEUH0.l
我尝试了以下方法,但文档说Swift中的枚举没有像C语言中那样分配基础整数值,所以我可能在错误的方向上努力了。
有更好的解决方法吗?
func deck() -> Card[]{
var deck: Card[]
for s in Suit {
for r in Rank {
deck += Card(rank: r, suit: s)
}
}
return deck
}
func deck2() -> Card[]{
var deck: Card[]
for var s: Suit = .Spades; s <= .Clubs; s++ {
for var r: Rank = .Ace; r <= .King; r++ {
deck += Card(rank: r, suit: s)
}
}
return deck
}