安卓，自定义state_pressed状态无效

Question

我的自定义选择器如下所示，没有按预期工作，我根本看不到 pressed 状态。有什么提示吗？谢谢

<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android"

    >
    <!-- this state button has special design:
        + enabled state has white text on green background
        + disabled state has grey text on greyer background
    -->


    <item android:state_enabled="true"
        android:drawable="@drawable/cb_shape_button_primary"
        android:color="@color/white"

        />
    <item android:state_pressed="true"
        android:drawable="@drawable/cb_shape_button_pressed"
        android:color="@color/white"

        />

    <item android:state_focused="true"
        android:drawable="@drawable/cb_shape_button_pressed"
        android:color="@color/white"

        />
    <item android:state_enabled="false"
        android:drawable="@drawable/cb_shape_button_flat"
        android:color="@color/grey_subtext"
        />

</selector>

- EyeQ Tech

---

状态列表Drawable和禁用状态 - TT--

Answer 1

尝试将state_pressed移动到顶部，像这样：

<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android"

>
<!-- this state button has special design:
    + enabled state has white text on green background
    + disabled state has grey text on greyer background
-->

<item android:state_pressed="true"
    android:drawable="@drawable/cb_shape_button_pressed"
    android:color="@color/white"

    />

<item android:state_enabled="true"
    android:drawable="@drawable/cb_shape_button_primary"
    android:color="@color/white"

    />

<item android:state_focused="true"
    android:drawable="@drawable/cb_shape_button_pressed"
    android:color="@color/white"

    />
<item android:state_enabled="false"
    android:drawable="@drawable/cb_shape_button_flat"
    android:color="@color/grey_subtext"
    />

编辑：
正如@forcewill所提到的，需要注意的是将按下状态移到顶部的原因是因为Android将使用与之匹配的第一个状态，在您的情况下，小部件同时启用和按下，因此首先匹配启用状态。

- Akshay Bhat 'AB'

---

请注意，将按下状态移至顶部的原因是因为Android将使用与之匹配的第一个状态。在您的情况下，小部件同时启用并已按下，因此它首先匹配启用状态。 - forcewill

Answer 2

选择器XML标签始终选择第一个匹配项。这意味着如果视图启用，则始终会显示@drawable/cb_shape_button_primary。选择器的一般准则是，默认项应该在列表中的最后一个。

尝试将默认状态移至最后，看看是否解决了您的问题。

<?xml version="1.0" encoding="utf-8"?>
<selector xmlns:android="http://schemas.android.com/apk/res/android"

    >
    <!-- this state button has special design:
        + enabled state has white text on green background
        + disabled state has grey text on greyer background
    -->

    <item android:state_pressed="true"
        android:drawable="@drawable/cb_shape_button_pressed"
        android:color="@color/white"

        />

    <item android:state_focused="true"
        android:drawable="@drawable/cb_shape_button_pressed"
        android:color="@color/white"

        />
    <item android:state_enabled="false"
        android:drawable="@drawable/cb_shape_button_flat"
        android:color="@color/grey_subtext"
        />

   <item android:state_enabled="true"
        android:drawable="@drawable/cb_shape_button_primary"
        android:color="@color/white"

        />

</selector>

- cyroxis

Answer 3

简单的选择和取消选择，请使用以下代码

<selector><item android:state_checked="false" android:drawable="@drawable/radiobtnunselected"/><item android:state_checked="true" android:drawable="@drawable/radiobtnselected"/></selector>

将您的图像设置为android:drawable

True：已选择

False：未选择

- Maulik Santoki

Answer 4

试试这个，

<selector xmlns:android="http://schemas.android.com/apk/res/android">
<item android:drawable="@drawable/select_item" android:state_checked="true" android:state_focused="true" />
<item android:drawable="@drawable/unselect_item" android:state_checked="false" android:state_focused="true" />
<item android:drawable="@drawable/unselect_item" android:state_checked="false" />
<item android:drawable="@drawable/select_item" android:state_checked="true" />

- Das

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你不仅应该发布代码，还要解释为什么提出这样的建议。 - cyroxis