如何避免第二个数组中的数组索引跳过?

4

如何遍历数组中的每个元素?

我想要的结果是:

Banana
0
Mango
1

当前结果:

Banana
0
Mango
3

代码如下:

<body>
<p id="demo"></p>
<script>
    var fruits, text, year, i;
    fruits = ["Banana", "Orange", "Apple", "Mango"];
    year = ["0", "1", "2", "3"];
    text = "<ul>";
    for (i = 0; i < fruits.length; i++) {
        switch (fruits[i]) {
            case 'Mango':
                text += "<li>" + fruits[i] + "</li>";
                text += "<li><b>" + year[i] + "</b></li>";
                break;
            case 'Pine apple':
                text += "<li>" + fruits[i] + "</li>";
                text += "<li><b>" + year[i] + "</b></li>";
                break;
            case 'Grape':
                text += "<li>" + fruits[i] + "</li>";
                text += "<li><b>" + year[i] + "</b></li>";
                break;
            case 'Banana':
                text += "<li>" + fruits[i] + "</li>";
                text += "<li><b>" + year[i] + "</b></li>";
                break;
        }
    }
    text += "</ul>";
    document.getElementById("demo").innerHTML = text;
</script>


你能详细说明你的问题吗?我不明白你所说的“不跳过数组顺序”是什么意思。 - Mossmyr
1个回答

2

按照常规方法遍历数组,并在水果与case语句匹配时增加第二个计数器。使用该计数器从数组中获取年份:

var fruits, text, year, i;
fruits = ["Banana", "Orange", "Apple", "Mango"];
year = ["0", "1", "2", "3"];
text = "<ul>";
let counter = 0; // <-- define a second counter
for (i = 0; i < fruits.length; i++) {
  switch (fruits[i]) {
    case 'Mango':
      text += "<li>" + fruits[i] + "</li>";
      text += "<li><b>" + year[counter] + "</b></li>";
      counter++; // <-- that only get's incremented when a case is matched
      break;
    case 'Pine apple':
      text += "<li>" + fruits[i] + "</li>";
      text += "<li><b>" + year[counter] + "</b></li>";
      counter++;
      break;
    case 'Grape':
      text += "<li>" + fruits[i] + "</li>";
      text += "<li><b>" + year[counter] + "</b></li>";
      counter++;
      break;
    case 'Banana':
      text += "<li>" + fruits[i] + "</li>";
      text += "<li><b>" + year[counter] + "</b></li>";
      counter++;
      break;
  }
}
text += "</ul>";
document.getElementById("demo").innerHTML = text;
<p id="demo"></p>


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