在Java中,我该如何将UTF-8输出为真正的字符串?
我们
\u6211\u4eec
String str = new String("\u6211\u4eec");
System.out.println(str); // still ouput \u6211\u4eec, but I expect 我们 to be an output
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String tmp = request.getParameter("tag");
System.out.println("request:"+tmp);
System.out.println("character set :"+request.getCharacterEncoding());
String tmp1 = new String("\u6211\u4eec");
System.out.println("string equal:"+(tmp.equalsIgnoreCase(tmp1)));
String tag = new String(tmp);
System.out.println(tag);
request:\u6211\u4eec
character set :UTF-8
string equal:false
\u6211\u4eec
从输出结果来看,请求中的值和tmp1
的字符串值是相同的,但为什么equalsIgnoreCase
的输出结果是false
?