我正在寻找在Windows命令提示符中告诉我特定DLL文件是32位还是64位的命令。在Windows中是否有这样的命令?
DUMPBIN
是Visual C++的一部分,可以使用/HEADERS
开关提供此信息。
32位映像的示例输出:
FILE HEADER VALUES
14C machine (i386)
6 number of sections
306F7A22 time date stamp Sun Oct 01 22:35:30 1995
0 file pointer to symbol table
1D1 number of symbols
E0 size of optional header
302 characteristics
Executable
32 bit word machine
Debug information stripped
"C:\Program Files\7-Zip\7z.exe" l "my-program.exe" | findstr CPU
#include <Windows.h>
#include <Dbghelp.h>
#include <string>
#include <iostream>
using namespace std;
bool GetImageFileHeaders(wstring fileName, IMAGE_NT_HEADERS &headers)
{
HANDLE fileHandle = CreateFile(
fileName.c_str(),
GENERIC_READ,
FILE_SHARE_READ,
nullptr,
OPEN_EXISTING,
FILE_ATTRIBUTE_NORMAL,
0
);
if (fileHandle == INVALID_HANDLE_VALUE)
return false;
HANDLE imageHandle = CreateFileMapping(
fileHandle,
nullptr,
PAGE_READONLY,
0,
0,
nullptr
);
if (imageHandle == 0)
{
CloseHandle(fileHandle);
return false;
}
void *imagePtr = MapViewOfFile(
imageHandle,
FILE_MAP_READ,
0,
0,
0
);
if (imagePtr == nullptr)
{
CloseHandle(imageHandle);
CloseHandle(fileHandle);
return false;
}
PIMAGE_NT_HEADERS headersPtr = ImageNtHeader(imagePtr);
if (headersPtr == nullptr)
{
UnmapViewOfFile(imagePtr);
CloseHandle(imageHandle);
CloseHandle(fileHandle);
return false;
}
headers = *headersPtr;
UnmapViewOfFile(imagePtr);
CloseHandle(imageHandle);
CloseHandle(fileHandle);
return true;
}
int main(int argc, char* argv[])
{
IMAGE_NT_HEADERS headers;
if (GetImageFileHeaders(L"C:\\windows\\system32\\user32.dll", headers))
{
if (headers.FileHeader.Machine == IMAGE_FILE_MACHINE_I386)
cout << "x86";
else if (headers.FileHeader.Machine == IMAGE_FILE_MACHINE_IA64)
cout << "IA64";
else if (headers.FileHeader.Machine == IMAGE_FILE_MACHINE_AMD64)
cout << "x64";
else
cout << "Machine not recognised";
}
return 0;
}
dbghelp.lib
添加到项目的附加依赖项中。要了解更多详细信息,请参阅MSDN文档,其中介绍用于各种API调用的方法。
dumpbin
和cygwin file.exe
也在那里提到。 - user184968