大家好,我希望我的英语足够好,能够解释清楚我的需求。
让我们来看这个代码示例(仅为示例):
class Something(){
public function Lower($string){
return strtolower($string);
}
}
class Foo{
public $something;
public $reg;
public $string;
public function __construct($reg, $string, $something){
$this->something = $something;
$this->reg = $reg;
$this->string = $string;
}
public function Replace(){
return preg_replace_callback($this->reg, 'Foo::Bar', $this->string);
}
public static function Bar($matches){
/*
* [...]
* do something with $matches and create the $output variable
* [...]
*/
/*
* I know is really useless in this example, but i need to have an istance to an object here
* (in this example, the Something object, but can be something else!)
*/
return $this->something->Lower($output);
}
}
$s = new Something();
$foo = new Foo($myregexp, $mystring, $s);
$content = $foo->Replace();
因此,PHP手册指出,在preg_replace_callback()
中使用类方法作为回调函数时,该方法必须是抽象的。
我需要在回调函数中传递一个先前初始化的对象的实例(在示例中,是Something
类的实例)。
我尝试使用call_user_func()
,但它不起作用(因为这样我会错过matches
参数)。
是否有一种方法可以做到这一点,或者我必须分开处理(在进行preg_match_all
之前,对于每个匹配检索替换值,然后使用简单的preg_replace
)?
编辑:在Tom Haigh的答案之前,我使用了这个解决方法(在示例中,这是Replace方法):
$has_dynamic = preg_match_all($this->reg, $this->string, $dynamic);
if($has_dynamic){
/*
* The 'usefull' subset of my regexp is the third, so $dynamic[2]
*/
foreach($dynamic[2] AS $key => $value){
$dynamic['replaces'][$key] = $this->Bar($value);
}
/*
* ..but i need to replace the complete subset, so $dynamic[0]
*/
return str_replace($dynamic[0], $dynamic['replaces'], $this->string);
}else{
return $this->string;
}
希望能帮助到某些人。