我正在使用这段代码:
import imaplib
mail = imaplib.IMAP4_SSL('imap.gmail.com')
mail.login(myusername, mypassword)
mail.list()
# Out: list of "folders" aka labels in gmail.
mail.select("inbox") # connect to inbox.
result, data = mail.search(None, "ALL")
ids = data[0] # data is a list.
id_list = ids.split() # ids is a space separated string
latest_email_id = id_list[-1] # get the latest
result, data = mail.fetch(latest_email_id, "(RFC822)") # fetch the email body (RFC822) for the given ID
raw_email = data[0][1] # here's the body, which is raw text of the whole email
# including headers and alternate payloads
print raw_email
除了一个问题以外,它可以正常工作。当我打印raw_email
时,会返回大量额外的信息。我该如何处理这些额外的信息并仅获取发件人和正文文本?
imaplib
和Python的email
包的API让我疯了,这个好多了! - xjcl