假设我有一个字符串,如下所示:
如果我使用
$thestring = "1,2,3,8,2"
。如果我使用
explode(',', $thestring)
,我会得到一个字符串数组。如何将其分解为整数数组?$thestring = "1,2,3,8,2"
。explode(',', $thestring)
,我会得到一个字符串数组。如何将其分解为整数数组?$data = explode( ',', $thestring );
array_walk( $data, 'intval' );
$data = array_map('intval',$data);
来代替。 - ParoX大多数情况下你不需要这样做(PHP通常可以很好地处理字符串和浮点/整数的强制转换), 但如果绝对必要,你可以使用array_walk
与intval
或floatval
:
$arr = explode(',','1,2,3');
// use floatval if you think you are going to have decimals
array_walk($arr,'intval');
print_r($arr);
Array
(
[0] => 1
[1] => 2
[2] => 3
)
settype
函数:$arr = explode(",","1,2,3");
function fn(&$a){settype($a,"int");}
array_walk($f,"fn");
print_r($f);
Array
(
[0] => 1
[1] => 2
[2] => 3
)
如果您正在尝试动态转换,这可能特别有用:
class Converter {
public $type = 'int';
public function cast(&$val){ settype($val, $this->type); }
}
$c = new Converter();
$arr = explode(",","1,2,3,0");
array_walk($arr,array($c, 'cast'));
print_r($arr);
Array
(
[0] => 1
[1] => 2
[2] => 3
[3] => 0
)
// now using a bool
$c->type = 'bool';
$arr = explode(",","1,2,3,0");
array_walk($arr,array($c, 'cast'));
var_dump($arr); // using var_dump because the output is clearer.
array(4) {
[0]=>
bool(true)
[1]=>
bool(true)
[2]=>
bool(true)
[3]=>
bool(false)
}
由于$thestring是字符串,因此您将获得一个字符串数组。
只需在分裂值前面添加(int)。
或使用array_walk函数:
$arr = explode(',', $thestring);
array_walk($arr, 'intval');
$thestring = "1,2,3,8,a,b,2";
$newArray = array();
$theArray = explode(",", $thestring);
print_r($theArray);
foreach ($theArray as $theData) {
if (is_numeric($theData)) {
$newArray[] = $theData;
}
}
print_r($newArray);
// 输出
原始数组
Array ( [0] => 1 [1] => 2 [2] => 3 [3] => 8 [4] => a [5] => b [6] => 2 )
只包含数字的数组
Array ( [0] => 1 [1] => 2 [2] => 3 [3] => 8 [4] => 2 )
$arr=explode(',', $thestring);
$newstr = '';
foreach($arr as $key=>$val){
$newstr .= $val;
}