我有一个应用程序，需要登录才能继续（例如使用Google）。
当需要身份验证时，我希望重定向用户。
但是，当我运行 Navigator.of(context).pushNamed("myroute") 时，我收到以下错误：
══╡ EXCEPTION CAUGHT BY WIDGETS LIBRARY ╞═══════════════════════════════════════════════════════════
I/flutter ( 5624): The following assertion was thrown building _ModalScopeStatus(active):
I/flutter ( 5624): setState() or markNeedsBuild() called during build.
I/flutter ( 5624): This Overlay widget cannot be marked as needing to build because the framework is already in the
I/flutter ( 5624): process of building widgets. A widget can be marked as needing to be built during the build phase
I/flutter ( 5624): only if one of its ancestors is currently building. This exception is allowed because the framework
I/flutter ( 5624): builds parent widgets before children, which means a dirty descendant will always be built.
I/flutter ( 5624): Otherwise, the framework might not visit this widget during this build phase.
这里是一个示例代码
void main() {
runApp(new MyApp());
}
class MyApp extends StatelessWidget {
@override
Widget build(BuildContext context) {
return new MaterialApp(
title: 'Flutter Demo',
theme: new ThemeData(
primarySwatch: Colors.blue,
),
home: new MyHomePage(title: 'Flutter Demo Home Page'),
routes: <String, WidgetBuilder> {
"login" : (BuildContext context) => new LoginPage(),
}
);
}
}
class MyHomePage extends StatefulWidget {
MyHomePage({Key key, this.title}) : super(key: key);
final String title;
@override
_MyHomePageState createState() => new _MyHomePageState();
}
class _MyHomePageState extends State<MyHomePage> {
int _counter = 0;
@override
void initState() {
super.initState();
if(!isLoggedIn) {
print("not logged in, going to login page");
Navigator.of(context).pushNamed("login");
}
}
void _incrementCounter() {
setState(() {
_counter++;
});
}
void test() {
print("hello");
}
@override
Widget build(BuildContext context) {
return new Scaffold(
appBar: new AppBar(
title: new Text(widget.title),
),
body: new Center(
child: new Text(
'Button tapped $_counter time${ _counter == 1 ? '' : 's' }.',
),
),
floatingActionButton: new FloatingActionButton(
onPressed: _incrementCounter,
tooltip: 'Increment',
child: new Icon(Icons.add),
), // This trailing comma makes auto-formatting nicer for build methods.
);
}
}
class LoginPage extends StatefulWidget {
LoginPage({Key key, this.title}) : super(key: key);
final String title;
@override
_LoginPageState createState() => new _LoginPageState();
}
class _LoginPageState extends State<LoginPage> {
@override
Widget build(BuildContext context) {
print("building login page");
return new Scaffold(
appBar: new AppBar(
title: new Text("Sign up / Log In"),
),
),
);
}
}
我猜我做错了什么，也许是中止小部件构建导致了这个问题。但是，我该如何实现这一点。
基本上： "我进入我的页面，如果没有登录，就转到登录页面"
谢谢， Alexi
context未定义。 - temirbekState有一个context实例属性，你可能正在尝试在无状态小部件或任何其他不是State<T>的类中调用它。此外，我建议在initState方法内调用它，因为我不太确定在build方法内调用它时所有可能的副作用。 - Guilherme Matuella