我遇到了一个问题，无法映射类的嵌入式属性。我创建了一些类来说明我试图做的事情。基本上，我有一个使用继承的@Embeddable类层次结构。顶级类“零件号”只有一个属性，扩展类不向“零件号”类添加任何属性，它们只添加一些验证/逻辑。
这是我的意思：
零件
@Entity
@Table(name="PART")
public class Part {
private Integer id;
private String name;
private PartNumber partNumber;
@Id
@GeneratedValue(strategy=GenerationType.SEQUENCE)
public Integer getId() {
return id;
}
public void setId(Integer id) {
this.id = id;
}
@Column(name="PART_NAME")
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
@Embedded
public PartNumber getPartNumber() {
return partNumber;
}
public void setPartNumber(PartNumber partNumber) {
this.partNumber = partNumber;
}
}
零件编号
@Embeddable
public abstract class PartNumber {
protected String partNumber;
private String generalPartNumber;
private String specificPartNumber;
private PartNumber() {
}
public PartNumber(String partNumber) {
this.partNumber = partNumber;
}
@Column(name = "PART_NUMBER")
public String getPartNumber() {
return partNumber;
}
public void setPartNumber(String partNumber) {
this.partNumber = partNumber;
}
/**
* @param partNumber
* @return
*/
public boolean validate(String partNumber) {
// do some validation
return true;
}
/**
* Returns the first half of the Part Number
*
* @return generalPartNumber
*/
@Transient
public String getGeneralPartNumber() {
return generalPartNumber;
}
/**
* Returns the last half of the Part Number
* which is specific to each Car Brand
*
* @return specificPartNumber
*/
@Transient
public String getSpecificPartNumber() {
return specificPartNumber;
}
}
FORD零件编号
public class FordPartNumber extends PartNumber {
/**
* Ford Part Number is formatted as 1234-#1234
*
* @param partNumber
*/
public FordPartNumber(String partNumber) {
super(partNumber);
validate(partNumber);
}
/*
* (non-Javadoc)
*
* @see com.test.PartNumber#validate(java.lang.String)
*/
@Override
public boolean validate(String partNumber) {
// do some validation
return true;
}
/*
* (non-Javadoc)
*
* @see com.test.PartNumber#getGeneralPartNumber()
*/
@Override
public String getGeneralPartNumber() {
return partNumber;
}
/*
* (non-Javadoc)
*
* @see com.test.PartNumber#getSpecificPartNumber()
*/
@Override
public String getSpecificPartNumber() {
return partNumber;
}
}
CHEVY零件号
public class ChevyPartNumber extends PartNumber {
/**
* Chevy Part Number is formatted as 1234-$1234
*
* @param partNumber
*/
public ChevyPartNumber(String partNumber) {
super(partNumber);
validate(partNumber);
}
/*
* (non-Javadoc)
*
* @see com.test.PartNumber#validate(java.lang.String)
*/
@Override
public boolean validate(String partNumber) {
// do some validation
return true;
}
/*
* (non-Javadoc)
*
* @see com.test.PartNumber#getGeneralPartNumber()
*/
@Override
public String getGeneralPartNumber() {
return partNumber;
}
/*
* (non-Javadoc)
*
* @see com.test.PartNumber#getSpecificPartNumber()
*/
@Override
public String getSpecificPartNumber() {
return partNumber;
}
}
当然这样做是行不通的，因为Hibernate忽略了继承层次结构，并且不喜欢PartNumber是抽象的这一事实。是否有一种使用JPA或Hibernate注释来解决此问题的方法？我已经尝试过使用@Inheritance JPA注释，但无法重构继承层次结构中的“PartNumber”部分，因为原始开发人员希望能够使用N个XXXXPartNumber类扩展PartNumber。是否有人知道像这样的东西是否将成为JPA 2.0或Hibernate的新版本的一部分？