类型错误：'in <string>' 需要左操作数为字符串而不是列表。

Question

我正在完成《笨办法学Python》（LPTHW）的第35个练习。

http://learnpythonthehardway.org/book/ex35.html

我正在苦恼于这个练习中的一个学习任务，具体来说是“添加更多游戏内容”。

以下是返回错误的代码:

def bear_room(): # A new encounter
    print "There is a bear here."
    print "The bear has a bunch of honey."
    print "The fat bear is in front of another door."
    print "How are you going to move the bear?"

    bear_moved = False 

while True: 
    next = str(raw_input("> "))

    if ["honey", "take"] in next: 
        dead("The bear peers at you for a moment, sizing you up, then claws your face off.")
    elif ["taunt", "lure", "yell", "scream", "shout"] in next:
        print "the bear has moved from the door. You can go through it now."
        bear_moved = True
    elif ["taunt", "lure", "yell", "scream", "shout"] in next and bear_moved: 
        dead("The bear gets pissed off and chews your leg off.")
    elif ["open", "door", "next", "through", "onward"] in next and bear_moved:
        gold_room()
    else:
        print "I got not idea what that means."

- Harrison Boles

Answer 1

你需要将代码中的测试条件改为：

next in ["嘲讽", "引诱", "喊叫", "尖叫", "呼喊"]

而不是

["嘲讽", "引诱", "喊叫", "尖叫", "呼喊"] in next

你的测试条件是反过来的。

- SpliFF

---

非常感谢，已经测试并确认可行！它们对我来说仍然看起来一样，显然它们不是一样的，但没关系！ - Harrison Boles

在这种情况下，顺序很重要，“钥匙在锁里”和“锁在钥匙里”是不同的。另外，请记得将答案标记为正确。 - SpliFF