我从服务器获得的JSON响应中返回了这样一个对象:
{
"0": "1",
"1": "2",
"2": "3",
"3": "4"
}
我想把它转换成这样的 JavaScript 数组:
["1","2","3","4"]
有没有最佳方法来完成这个任务?我看到很多人都在使用循环的复杂逻辑。那么除了循环之外,还有其他的方法吗?
我从服务器获得的JSON响应中返回了这样一个对象:
{
"0": "1",
"1": "2",
"2": "3",
"3": "4"
}
我想把它转换成这样的 JavaScript 数组:
["1","2","3","4"]
有没有最佳方法来完成这个任务?我看到很多人都在使用循环的复杂逻辑。那么除了循环之外,还有其他的方法吗?
使用原生JavaScript,假设您有以下内容:
var j = {0: "1", 1: "2", 2: "3", 3: "4"};
Object.keys(j).map(function(_) { return j[_]; })
输出:
["1", "2", "3", "4"]
var obj = {"0":"1","1":"2","2":"3","3":"4"};
var arr = [];
json = JSON.stringify(eval('(' + obj + ')')); //convert to json string
arr = $.parseJSON(json); //convert to javascript array
被接受的解决方案期望键从0开始并且连续 - 它将值存入数组,但在此过程中丢失了索引。
如果您的“具有数字键的对象”不符合这些更严格的假设,请使用此选项。
//let sourceObject = ...
let destinationArray = [];
Object.keys(sourceObject).forEach(k => destinationArray[k] = sourceObject[k]);
function osort(obj)
{ // map the object to an array [key, obj[key]]
return Object.keys(obj).map(function(key) { return [key, obj[key]] }).sort(
function (keya, keyb)
{ // sort(from largest to smallest)
return keyb[1] - keya[1];
}
);
}
这是最好的解决方案。我认为是这样。
Object.keys(obj).map(function(k){return {key: k, value: obj[k]}})
$data='{"resultList":[{"id":"1839","displayName":"Analytics","subLine":""},{"id":"1015","displayName":"Automation","subLine":""},{"id":"1084","displayName":"Aviation","subLine":""},{"id":"554","displayName":"Apparel","subLine":""},{"id":"875","displayName":"Aerospace","subLine":""},{"id":"1990","displayName":"Account Reconciliation","subLine":""},{"id":"3657","displayName":"Android","subLine":""},{"id":"1262","displayName":"Apache","subLine":""},{"id":"1440","displayName":"Acting","subLine":""},{"id":"710","displayName":"Aircraft","subLine":""},{"id":"12187","displayName":"AAC","subLine":""}, {"id":"20365","displayName":"AAT","subLine":""}, {"id":"7849","displayName":"AAP","subLine":""}, {"id":"20511","displayName":"AACR2","subLine":""}, {"id":"28585","displayName":"AASHTO","subLine":""}, {"id":"45191","displayName":"AAMS","subLine":""}]}';
$b=json_decode($data);
$i=0;
while($b->{'resultList'}[$i])
{
print_r($b->{'resultList'}[$i]->{'displayName'});
echo "<br />";
$i++;
}
var data = [];
data = {{ jdata|safe }}; //parse through js
var i = 0 ;
for (i=0;i<data.length;i++){
data[i] = data[i].value;
}