我想在iPhone OS 3.1.3中使用CATiledLayer,为此,所有绘图都必须仅使用coregraphics在
现在,我遇到了iPhone上翻转坐标系统的问题,并有一些建议如何使用变换来解决: 我的问题是我无法让它正常工作。我开始使用PhotoScroller示例代码,并用仅限于coregraphics调用的绘图方法替换了它。它看起来像这样:
这是它的外观:
原则上,由于核心图形库使用像素而不是点来工作,因此忽略显示的比例尺。因此,在要求绘制更多像素时,将使用更多的CATiledLayers(或子层)来填充屏幕。
感谢 Thomas
-(void)drawLayer:(CALayer *)layer inContext:(CGContext)context
中完成。现在,我遇到了iPhone上翻转坐标系统的问题,并有一些建议如何使用变换来解决: 我的问题是我无法让它正常工作。我开始使用PhotoScroller示例代码,并用仅限于coregraphics调用的绘图方法替换了它。它看起来像这样:
- (void)drawLayer:(CALayer *)layer inContext:(CGContextRef)context {
CGContextSaveGState(context);
CGRect rect = CGContextGetClipBoundingBox(context);
CGFloat scale = CGContextGetCTM(context).a;
CGContextConcatCTM(context, CGAffineTransformMakeTranslation(0.f, rect.size.height));
CGContextConcatCTM(context, CGAffineTransformMakeScale(1.f, -1.f));
CATiledLayer *tiledLayer = (CATiledLayer *)layer;
CGSize tileSize = tiledLayer.tileSize;
tileSize.width /= scale;
tileSize.height /= scale;
// calculate the rows and columns of tiles that intersect the rect we have been asked to draw
int firstCol = floorf(CGRectGetMinX(rect) / tileSize.width);
int lastCol = floorf((CGRectGetMaxX(rect)-1) / tileSize.width);
int firstRow = floorf(CGRectGetMinY(rect) / tileSize.height);
int lastRow = floorf((CGRectGetMaxY(rect)-1) / tileSize.height);
for (int row = firstRow; row <= lastRow; row++) {
for (int col = firstCol; col <= lastCol; col++) {
// if (row == 0 ) continue;
UIImage *tile = [self tileForScale:scale row:row col:col];
CGImageRef tileRef = [tile CGImage];
CGRect tileRect = CGRectMake(tileSize.width * col, tileSize.height * row,
tileSize.width, tileSize.height);
// if the tile would stick outside of our bounds, we need to truncate it so as to avoid
// stretching out the partial tiles at the right and bottom edges
tileRect = CGRectIntersection(self.bounds, tileRect);
NSLog(@"row:%d, col:%d, x:%.0f y:%.0f, height:%.0f, width:%.0f", row, col,tileRect.origin.x, tileRect.origin.y, tileRect.size.height, tileRect.size.width);
//[tile drawInRect:tileRect];
CGContextDrawImage(context, tileRect, tileRef);
// just to draw the row and column index in the tile and mark the origin of the tile with a red line
if (self.annotates) {
CGContextSetStrokeColorWithColor(context, [[UIColor whiteColor]CGColor]);
CGContextSetLineWidth(context, 6.0 / scale);
CGContextStrokeRect(context, tileRect);
CGContextSetStrokeColorWithColor(context, [[UIColor redColor]CGColor]);
CGContextMoveToPoint(context, tileRect.origin.x, tileRect.origin.y);
CGContextAddLineToPoint(context, tileRect.origin.x+100.f, tileRect.origin.y+100.f);
CGContextStrokePath(context);
CGContextSetStrokeColorWithColor(context, [[UIColor redColor]CGColor]);
CGContextSetFillColorWithColor(context, [[UIColor whiteColor]CGColor]);
CGContextSelectFont(context, "Courier", 128, kCGEncodingMacRoman);
CGContextSetTextDrawingMode(context, kCGTextFill);
CGContextSetShouldAntialias(context, true);
char text[30];
int length = sprintf(text,"row:%d col:%d",row,col);
CGContextSaveGState(context);
CGContextShowTextAtPoint(context, tileRect.origin.x+110.f,tileRect.origin.y+100.f, text, length);
CGContextRestoreGState(context);
}
}
}
CGContextRestoreGState(context);
}
如您所见,我正在使用比例变换来反转坐标系,并使用平移变换将原点移动到左下角。图像绘制正确,但只绘制了第一行瓷砖。我认为平移操作或计算瓷砖坐标的方式存在问题。这是它的外观:
我对所有这些转换有点困惑。
奖励问题: 如何在核心图形中处理视网膜显示图片?
编辑: 为了使其在视网膜显示器上正常工作,我只是采用了示例代码中提供图像的原始方法:
- (UIImage *)tileForScale:(CGFloat)scale row:(int)row col:(int)col
{
// we use "imageWithContentsOfFile:" instead of "imageNamed:" here because we don't want UIImage to cache our tiles
NSString *tileName = [NSString stringWithFormat:@"%@_%d_%d_%d", imageName, (int)(scale * 1000), col, row];
NSString *path = [[NSBundle mainBundle] pathForResource:tileName ofType:@"png"];
UIImage *image = [UIImage imageWithContentsOfFile:path];
return image;
}
原则上,由于核心图形库使用像素而不是点来工作,因此忽略显示的比例尺。因此,在要求绘制更多像素时,将使用更多的CATiledLayers(或子层)来填充屏幕。
感谢 Thomas