我正在尝试使用Java播放*.wav文件,希望做到以下几点:
当按下按钮时,播放短蜂鸣声。
我已经在谷歌上搜索了,但大部分代码都无法正常工作。有没有人能给我一个简单的代码片段来播放.wav文件?
最终我成功地完成了以下操作,并且它运行得很好。
import java.io.File;
import java.io.IOException;
import javax.sound.sampled.AudioFormat;
import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.DataLine;
import javax.sound.sampled.LineUnavailableException;
import javax.sound.sampled.SourceDataLine;
public class MakeSound {
private final int BUFFER_SIZE = 128000;
private File soundFile;
private AudioInputStream audioStream;
private AudioFormat audioFormat;
private SourceDataLine sourceLine;
/**
* @param filename the name of the file that is going to be played
*/
public void playSound(String filename){
String strFilename = filename;
try {
soundFile = new File(strFilename);
} catch (Exception e) {
e.printStackTrace();
System.exit(1);
}
try {
audioStream = AudioSystem.getAudioInputStream(soundFile);
} catch (Exception e){
e.printStackTrace();
System.exit(1);
}
audioFormat = audioStream.getFormat();
DataLine.Info info = new DataLine.Info(SourceDataLine.class, audioFormat);
try {
sourceLine = (SourceDataLine) AudioSystem.getLine(info);
sourceLine.open(audioFormat);
} catch (LineUnavailableException e) {
e.printStackTrace();
System.exit(1);
} catch (Exception e) {
e.printStackTrace();
System.exit(1);
}
sourceLine.start();
int nBytesRead = 0;
byte[] abData = new byte[BUFFER_SIZE];
while (nBytesRead != -1) {
try {
nBytesRead = audioStream.read(abData, 0, abData.length);
} catch (IOException e) {
e.printStackTrace();
}
if (nBytesRead >= 0) {
@SuppressWarnings("unused")
int nBytesWritten = sourceLine.write(abData, 0, nBytesRead);
}
}
sourceLine.drain();
sourceLine.close();
}
}
这是我能想到的不使用 sun.* 的最优雅形式:
import java.io.*;
import javax.sound.sampled.*;
try {
File yourFile;
AudioInputStream stream;
AudioFormat format;
DataLine.Info info;
Clip clip;
stream = AudioSystem.getAudioInputStream(yourFile);
format = stream.getFormat();
info = new DataLine.Info(Clip.class, format);
clip = (Clip) AudioSystem.getLine(info);
clip.open(stream);
clip.start();
}
catch (Exception e) {
//whatevers
}
clip.start()
之后尝试加入 Thread.sleep(1000)
。 - Metaphore最短的形式(不需要安装任何随机库)?
public static void play(String filename)
{
try
{
Clip clip = AudioSystem.getClip();
clip.open(AudioSystem.getAudioInputStream(new File(filename)));
clip.start();
}
catch (Exception exc)
{
exc.printStackTrace(System.out);
}
}
唯一的问题是没有好的方法来使这个方法阻塞以便在*.wav完成后关闭和处理数据。
clip.drain()
说它是阻塞的,但实际上不是。剪辑片段并没有立即在start()
之后运行。
我发现的唯一可行但丑陋的方法是:
// ...
clip.start();
while (!clip.isRunning())
Thread.sleep(10);
while (clip.isRunning())
Thread.sleep(10);
clip.close();
import java.io.File;
import javax.sound.sampled.*;
public void play(File file)
{
try
{
final Clip clip = (Clip)AudioSystem.getLine(new Line.Info(Clip.class));
clip.addLineListener(new LineListener()
{
@Override
public void update(LineEvent event)
{
if (event.getType() == LineEvent.Type.STOP)
clip.close();
}
});
clip.open(AudioSystem.getAudioInputStream(file));
clip.start();
}
catch (Exception exc)
{
exc.printStackTrace(System.out);
}
}
这个代码片段可以正常工作,经过测试可用于播放Windows声音:
public static void main(String[] args) {
AePlayWave aw = new AePlayWave( "C:\\WINDOWS\\Media\\tada.wav" );
aw.start();
}
一个可以播放WAV文件的类,会阻塞直到声音播放完毕:
class Sound implements Playable {
private final Path wavPath;
private final CyclicBarrier barrier = new CyclicBarrier(2);
Sound(final Path wavPath) {
this.wavPath = wavPath;
}
@Override
public void play() throws LineUnavailableException, IOException, UnsupportedAudioFileException {
try (final AudioInputStream audioIn = AudioSystem.getAudioInputStream(wavPath.toFile());
final Clip clip = AudioSystem.getClip()) {
listenForEndOf(clip);
clip.open(audioIn);
clip.start();
waitForSoundEnd();
}
}
private void listenForEndOf(final Clip clip) {
clip.addLineListener(event -> {
if (event.getType() == LineEvent.Type.STOP) waitOnBarrier();
});
}
private void waitOnBarrier() {
try {
barrier.await();
} catch (final InterruptedException ignored) {
} catch (final BrokenBarrierException e) {
throw new RuntimeException(e);
}
}
private void waitForSoundEnd() {
waitOnBarrier();
}
}
AudioInputStream
实现的方法是:
import java.io.File;
import javax.sound.sampled.AudioInputStream;
import javax.sound.sampled.AudioSystem;
import javax.sound.sampled.Clip;
import javax.sound.sampled.Line;
import javax.sound.sampled.LineEvent;
import javax.sound.sampled.LineListener;
import javax.swing.JDialog;
import javax.swing.JFileChooser;
public class CoreJavaSound extends Object implements LineListener {
File soundFile;
JDialog playingDialog;
Clip clip;
public static void main(String[] args) throws Exception {
CoreJavaSound s = new CoreJavaSound();
}
public CoreJavaSound() throws Exception {
JFileChooser chooser = new JFileChooser();
chooser.showOpenDialog(null);
soundFile = chooser.getSelectedFile();
System.out.println("Playing " + soundFile.getName());
Line.Info linfo = new Line.Info(Clip.class);
Line line = AudioSystem.getLine(linfo);
clip = (Clip) line;
clip.addLineListener(this);
AudioInputStream ais = AudioSystem.getAudioInputStream(soundFile);
clip.open(ais);
clip.start();
}
public void update(LineEvent le) {
LineEvent.Type type = le.getType();
if (type == LineEvent.Type.OPEN) {
System.out.println("OPEN");
} else if (type == LineEvent.Type.CLOSE) {
System.out.println("CLOSE");
System.exit(0);
} else if (type == LineEvent.Type.START) {
System.out.println("START");
playingDialog.setVisible(true);
} else if (type == LineEvent.Type.STOP) {
System.out.println("STOP");
playingDialog.setVisible(false);
clip.close();
}
}
}
extends Object
? - MazeOfEncryption一种不使用Java反射的解决方案:DataLine.Info info = new DataLine.Info(SourceDataLine.class, audioFormat)
Java反射会降低性能。
运行: java playsound absoluteFilePathTo/file.wav
import javax.sound.sampled.*;
import java.io.*;
public class playsound {
public static void main (String args[]) throws Exception {
playSound (args[0]);
}
public static void playSound () throws Exception {
AudioInputStream
audioStream = AudioSystem.getAudioInputStream(new File (filename));
int BUFFER_SIZE = 128000;
AudioFormat audioFormat = null;
SourceDataLine sourceLine = null;
audioFormat = audioStream.getFormat();
sourceLine = AudioSystem.getSourceDataLine(audioFormat);
sourceLine.open(audioFormat);
sourceLine.start();
int nBytesRead = 0;
byte[] abData = new byte[BUFFER_SIZE];
while (nBytesRead != -1) {
try {
nBytesRead =
audioStream.read(abData, 0, abData.length);
} catch (IOException e) {
e.printStackTrace();
}
if (nBytesRead >= 0) {
int nBytesWritten = sourceLine.write(abData, 0, nBytesRead);
}
}
sourceLine.drain();
sourceLine.close();
}
}
我采用了 @greenLizard 的代码,并使其更加健壮。
AudioInputStream
。BufferedInputStream
。 因为 AudioSystem
的 getAudioInputStream
偶尔会抛出 IOException
,因为 getAutoInputSytream
方法无法备份输入流并重新开始。希望不再发现任何异常。
这是修改后的代码。 ErrorDisplayDialog 在 Java Swing 应用程序中将异常显示为 JDialog
。只需用 e.printStackTrace();
替换即可。
private void playWavFile(String fileName) {
InputStream inputStream = getClass().getResourceAsStream(fileName);
BufferedInputStream bufferedInputStream = new BufferedInputStream(
inputStream);
AudioInputStream audioStream = null;
AudioFormat audioFormat = null;
try {
audioStream = AudioSystem.getAudioInputStream(bufferedInputStream);
audioFormat = audioStream.getFormat();
} catch (UnsupportedAudioFileException e) {
new ErrorDisplayDialog(view.getFrame(),
"UnsupportedAudioFileException", e);
return;
} catch (IOException e) {
new ErrorDisplayDialog(view.getFrame(), "IOException", e);
return;
}
DataLine.Info info = new DataLine.Info(SourceDataLine.class,
audioFormat);
SourceDataLine sourceLine;
try {
sourceLine = (SourceDataLine) AudioSystem.getLine(info);
sourceLine.open(audioFormat);
} catch (LineUnavailableException e) {
new ErrorDisplayDialog(view.getFrame(), "LineUnavailableException",
e);
return;
}
sourceLine.start();
int nBytesRead = 0;
byte[] abData = new byte[128000];
while (nBytesRead != -1) {
try {
nBytesRead = audioStream.read(abData, 0, abData.length);
} catch (IOException e) {
new ErrorDisplayDialog(view.getFrame(), "IOException", e);
return;
}
if (nBytesRead >= 0) {
sourceLine.write(abData, 0, nBytesRead);
}
}
sourceLine.drain();
sourceLine.close();
try {
audioStream.close();
} catch (IOException e) {
new ErrorDisplayDialog(view.getFrame(), "IOException", e);
}
}
你也可以这样使用 AudioStream:
import java.awt.event.ActionEvent;
import java.awt.event.ActionListener;
import java.io.FileInputStream;
import java.io.FileNotFoundException;
import java.io.IOException;
import java.io.InputStream;
import javax.swing.JButton;
import javax.swing.JFrame;
import javax.swing.JPanel;
import sun.audio.AudioPlayer;
import sun.audio.AudioStream;
public class AudioWizz extends JPanel implements ActionListener {
private static final long serialVersionUID = 1L; //you like your cereal and the program likes their "serial"
static AudioWizz a;
static JButton playBuddon;
static JFrame frame;
public static void main(String arguments[]){
frame= new JFrame("AudioWizz");
frame.setSize(300,300);
frame.setVisible(true);
a= new AudioWizz();
playBuddon= new JButton("PUSH ME");
playBuddon.setBounds(10,10,80,30);
playBuddon.addActionListener(a);
frame.add(playBuddon);
frame.add(a);
}
public void actionPerformed(ActionEvent e){ //an eventListener
if (e.getSource() == playBuddon) {
try {
InputStream in = new FileInputStream("*.wav");
AudioStream sound = new AudioStream(in);
AudioPlayer.player.start(sound);
} catch(FileNotFoundException e1) {
e1.printStackTrace();
} catch (IOException e1) {
e1.printStackTrace();
}
}
}
}
AudioInputStream
从未关闭。 - Gilbert Le Blanc