我想使用当前 Hyper 的主支(master branch)编写一个服务器,该服务器会保存由 POST 请求传递的消息,并将此消息发送给每个传入的 GET 请求。
我有以下代码,大部分是从 Hyper 的示例目录中复制来的:
extern crate futures;
extern crate hyper;
extern crate pretty_env_logger;
use futures::future::FutureResult;
use hyper::{Get, Post, StatusCode};
use hyper::header::{ContentLength};
use hyper::server::{Http, Service, Request, Response};
use futures::Stream;
struct Echo {
data: Vec<u8>,
}
impl Echo {
fn new() -> Self {
Echo {
data: "text".into(),
}
}
}
impl Service for Echo {
type Request = Request;
type Response = Response;
type Error = hyper::Error;
type Future = FutureResult<Response, hyper::Error>;
fn call(&self, req: Self::Request) -> Self::Future {
let resp = match (req.method(), req.path()) {
(&Get, "/") | (&Get, "/echo") => {
Response::new()
.with_header(ContentLength(self.data.len() as u64))
.with_body(self.data.clone())
},
(&Post, "/") => {
//self.data.clear(); // argh. &self is not mutable :(
// even if it was mutable... how to put the entire body into it?
//req.body().fold(...) ?
let mut res = Response::new();
if let Some(len) = req.headers().get::<ContentLength>() {
res.headers_mut().set(ContentLength(0));
}
res.with_body(req.body())
},
_ => {
Response::new()
.with_status(StatusCode::NotFound)
}
};
futures::future::ok(resp)
}
}
fn main() {
pretty_env_logger::init().unwrap();
let addr = "127.0.0.1:12346".parse().unwrap();
let server = Http::new().bind(&addr, || Ok(Echo::new())).unwrap();
println!("Listening on http://{} with 1 thread.", server.local_addr().unwrap());
server.run().unwrap();
}
如何将看起来像是一系列数据块的req.body()
(似乎是一个Stream
)转换为Vec<u8>
?我猜想我必须返回一个消费该Stream
并将其转换为单个Vec<u8>
的Future
,也许可以使用fold()
。但我不知道该如何做。
Mutex
、Atomic*
或RwLock
。 - Shepmaster