我曾在 Powershell 中使用闭包来创建具有静态和实例方法的类,是否有更好的方法?
创建一个带有静态 "方法" 的对象。
function person_get_type {
return 'Person'
}
function make_person {
param
(
[parameter(mandatory=$true)][string]$name)
$properties = @{'name'=$name;'get_type'=$null}
$person = New-Object –TypeName PSObject –Prop $properties
$person.get_type = ${function:person_get_type}
return $person
}
$person = make_person -name 'James'
$type = $person.get_type.InvokeReturnAsIs()
Write-Host $type
创建一个带有实例“方法”的对象。
function dog_get_type {
return 'Dog'
}
function dog_make_get_name{
param
(
[Parameter(Mandatory=$true)][System.Management.Automation.PSObject]$self
)
return {return $self.name}.GetNewClosure()
}
function dog_make_set_name{
param
(
[Parameter(Mandatory=$true)][System.Management.Automation.PSObject]$self
)
return {param([parameter(mandatory=$true)][string]$name) $self.name = $name}.GetNewClosure()
}
function make_dog {
param
(
[parameter(mandatory=$true)][string]$name
)
$properties = @{'name'=$name;'get_type'=$null;'get_name'=$null;'set_name'=$null}
$dog = New-Object –TypeName PSObject –Prop $properties
$dog.get_type = ${function:dog_get_type}
$dog.get_name = dog_make_get_name -self $dog
$dog.set_name = dog_make_set_name -self $dog
return $dog
}
$dog = make_dog -name 'Spot'
$name = $dog.get_name.InvokeReturnAsIs()
Write-Host $name
$dog.set_name.Invoke("Paws")
$name = $dog.get_name.InvokeReturnAsIs()
Write-Host $name
$stuff = @($person,$dog)
foreach($thing in $stuff) {
Write-Host $thing.get_type.InvokeReturnAsIs()
}
我知道可以使用以下方法:
$object = New-Module -AsCustomObject -ScriptBlock {...}
但我认为使用这种方法无法创建实例方法。