我已经花了大部分时间尝试删除交集,因为 MySQL 并不支持。如果有人能提供一些指示,那将非常有帮助。
SELECT *, DATE_FORMAT(NOW(), '%Y') - DATE_FORMAT(dob, '%Y') - (DATE_FORMAT(NOW(), '00-%m-%d') < DATE_FORMAT(dob, '00-%m-%d')) AS age
FROM user U, user_utilisation UU
WHERE U.id_user = UU.id_user AND cp >= 1 AND cp <= 3000 AND sexe = 'M' AND UU.id_mailing = 6
GROUP BY U.id_user
HAVING age >= 1 AND age <= 100
ORDER BY nom, prenom
INTERSECT
SELECT *, DATE_FORMAT(NOW(), '%Y') - DATE_FORMAT(dob, '%Y') - (DATE_FORMAT(NOW(), '00-%m-%d') < DATE_FORMAT(dob, '00-%m-%d')) AS age
FROM user U, user_utilisation UU
WHERE U.id_user = UU.id_user AND cp >= 1 AND cp <= 3000 AND sexe = 'M' AND UU.id_mailing = 7
GROUP BY U.id_user
HAVING age >= 1 AND age <= 100
ORDER BY nom, prenom
我尝试使用JOIN
,但目前的情况如下:
SELECT *, DATE_FORMAT(NOW(), '%Y') - DATE_FORMAT(naissance, '%Y') - (DATE_FORMAT(NOW(), '00-%m-%d') < DATE_FORMAT(naissance, '00-%m-%d')) AS age
FROM user U, user_utilisation UU
WHERE U.id_user = UU.id_user AND cp >= 1 AND cp <= 3000 AND sexe = 'M'
AND UU.id_user IN (select id_user from user_utilisation where id_mailing = 6 OR id_mailing = 7)
HAVING age >= 1 AND age <= 100
ORDER BY nom, prenom
但是如果移除
GROUP BY
,我发现查询选中了2条记录,其中id_mailing = 1
,而GROUP BY
则隐藏了错误的记录。我相信这可能会引起问题...
user_utilisation
只有三个字段:id_user
、id_mailing
和date
。